The graph of part of linear function p is shown on the grid.
2 answers:
Answer:
A
Step-by-step explanation:
The domain of a function is the span of x-values covered by the graph.
From the graph, we can see that it stretches from x=-7 to x=2.
However, note that at x=-7, the dot is closed (shaded in). In other words, x=-7 <em>is</em> in our domain.
On the other hand, at x=2, the dot is not shaded. So, x=2 is <em>not</em> included in our domain.
Therefore, our domain all are numbers between -7 and 2 including -7 (and not including 2).
As a compound inequality, this is:
So, our answer is A.
Also note that we use x instead of p(x) because the domain relates to the x-variable. If we were to instead find the range, then we would use p(x).
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Answer:
The values of x and y in the diagonals of the parallelogram are x=0 and y=5
Step-by-step explanation:
Given that ABCD is a parallelogram
And segment AC=4x+10
From the figure we have the diagonals AC=3x+y and BD=2x+y
By the property of parallelogram the diagonals are congruent
∴ we can equate the diagonals AC=BD
That is 3x+y=2x+y
3x+y-(2x+y)=2x+y-(2x+y)
3x+y-2x-y=2x+y-2x-y
x+0=0 ( by adding the like terms )
∴ x=0
Given that segment AC=4x+10
Substitute x=0 we have AC=4(0)+10
=0+10
=10
∴ AC=10
Now (3x+y)+(2x+y)=10
5x+2y=10
Substitute x=0, 5(0)+2y=10
2y=10
∴ y=5
∴ the values of x and y are x=0 and y=5