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enot [183]
3 years ago
7

F(x) = 4x^2 + 3x - 11 f(-3)

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
3 0
Just plus in x for -3
f(x) = 4(-3)^2 + 3(-3) - 11
f (x) = 4(9) -9 - 11
f(x) = 36 - 20
f(x) = 16
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Pls Help Choose the correct word to complete the statement: If BC intersects circle A only at point B, and mCBA = 90°, then CB i
cricket20 [7]

Line CB touches circle A only at one point (point B), hence CB is a tangent.

<h3>What is a circle?</h3>

A circle is the locus of a point such that its distance from a fixed point (center) is always constant.

When a line intersects a circle in exactly one point the line is said to be tangent to the circle

Hence since Line CB touches circle A only at one point (point B), hence CB is a tangent.

Find out more on circle at: brainly.com/question/24375372

7 0
2 years ago
Which value of x will make the triangles similar by the SSS similarity theorem
masha68 [24]

Answer:

x = 30.

Step-by-step explanation:

For the triangles to be similar corresponding sides must be in the same ratio.

So 50/ 75 = x / 45

75x = 50*45

x = 50* 45/75

= 2 * 45 / 3

= 30.   (answer).


4 0
3 years ago
A grocery store clerk has 16 oranges, 20 apples, and 24 pears. The clerk needs to put an equal number of apples, oranges, and pe
GalinKa [24]

Answer:

4 oranges, 5 apples, 6 pears in each bag

Step-by-step explanation:

theyre all divisible by 4

7 0
3 years ago
Read 2 more answers
recall that two angles are supplementary if the sum of their measure is 180. find the measures of two supplementary angles if on
aleksklad [387]

Answer:

I don't know if it's correct

but I tried

Step-by-step explanation:

let the angle be x

20+4x+x=180

20+5x=180

5x=160

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5 0
3 years ago
A tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24. The players were still hungry so the coa
g100num [7]

The cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

<h3><u>Solution:</u></h3>

Let "f" be the cost of 1 fries

Let "h" be the cost of 1 hamburger

<em><u>Given that, tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24</u></em>

8 x cost of 1 hamburger + 5 x cost of 1 fries = 24

8 \times h + 5 \times f = 24

8h + 5f = 24 -------- eqn 1

<em><u>The players were still hungry so the coach bought six more hamburgers and two more fries for $16.60</u></em>

6 x cost of 1 hamburger + 2 x cost of 1 fries = 16.60

6 \times h + 2 \times f = 16.60

6h + 2f = 16.60 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

16h + 10f = 48 ------ eqn 3

Multiply eqn 2 by 5

30h + 10f = 83 -------- eqn 4

<em><u>Subtract eqn 3 from eqn 4</u></em>

30h + 10f = 83

16h + 10f = 48

( - ) ----------------------

14h = 35

<h3>h = 2.5</h3>

Substitute h = 2.5 in eqn 1

8(2.5) + 5f = 24

20 + 5f = 24

5f = 4

<h3>f = 0.8</h3>

Thus cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

5 0
3 years ago
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