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Ahat [919]
3 years ago
5

Solve 3/4h - 12 = 8 5/8​

Mathematics
1 answer:
DerKrebs [107]3 years ago
5 0

Answer:

Step-by-step explanation:

3/4h-12=8 5/8

       +12   +12

       3/4h= 20 5/8

      Divide by 3/4 on both sides

        h=   27 1/2

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inysia [295]

Answer:

40.92

Step-by-step explanation:

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Answer:

its the second one

Step-by-step explanation:

6 0
3 years ago
A point Q on a segment with endpoints A (2, −1) and C (4, 2) partitions the segment in a 4:1 ratio. Find Q.
Annette [7]

The point Q on a line segment with end points(2,1) and (4,2) is Q(12/5, -2/5)

<h3>What is a line segment?</h3>

A line segment is a straight line that passes through two given points.

The end points of the line determine how long or short a given line segment would be.

Analysis:

point Q(x, y )

x = \frac{MX1 + NX2}{M+N}

y = \frac{MY1 + MY2}{M+N}

where M :N = 4:1

x1 = 2, x2 = 4, y1 = -1, y2 = 2

x = \frac{4(2) +1(4)}{4+1} = 12/5

y = \frac{4(-1) + 1(2)}{4+1} = -2/5

In conclusion, the point Q is (12/5, -2/5).

Learn more about line segment: brainly.com/question/2437195

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3 0
2 years ago
If a woman takes an early pregnancy test, she will either test positive, meaning that the test says she is pregnant, or test neg
k0ka [10]

Answer:

0.0098

Step-by-step explanation:

Probability of being pregnant:100/1000

=1/10.

98% chance:=98/100 ×1/10

=98/1000

Therefore the probability that she really is pregnant is: 0.098

3 0
3 years ago
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
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