Differentiate f(x) = \frac{x^{3}-4 x+1}{x^{3}}.
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Answer:
null hypothesis is p=0.41
alternate hypothesis is p<0.41
Sample proportion is 0.36
critical value for a = 0.01 is -2.2326
z-statistic is −1,0166
critical value for the level of significance 0.10 is -1.28155
we fail to reject the null hypothesis in 0.01 significance level.
Step-by-step explanation:
Let p be the proportion of the viewing audience of 11:00PM CBS newscast in the area. Then
: p=0.41
: p<0.41
Sample proportion is 0.36 and critical value (left tailed) for a=0.01 is -2.2326
sample proportion Z-score can be calculated as follows:
z(0.36)= where
- p(s) is the sample proportion of vieved newscast (0.36)
- p is the proportion assumed under null hypothesis. (0.41)
- N is the sample size (100)
putting the numbers z(0.36)= =−1,0166
if the level of significance is 0.10 then critical value would be -1.28155.
in 0.01 significance level sample mean is not in the critical region, therefore we fail to reject the null hypothesis.