Question

Differentiate f(x) = \frac{x^{3}-4 x+1}{x^{3}}.

Answer 1

$f(x) = \frac{x^{3}-4 x+1}{x^{3}}\\ f'(x)=\frac{(3x^2-4)\cdot x^3-(x^3-4x+1)\cdot3x^2}{x^6}\\ f'(x)=\frac{x^2(3x^3-4x-3x^3+12x-3)}{x^6}\\ f'(x)=\frac{8x-3}{x^4}$