Answer:
Solving the expression
we get 6
The answer is 6.
Step-by-step explanation:
We need to find value of expression: ![\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B%5Csqrt%5B6%5D%7B8%7D%20%7D.%5Csqrt%7B2%7D-%28-%5Cfrac%7B18%7D%7B%5Csqrt%7B81%7D%20%7D%20-2%29)
We know that 
Our expression will become
![\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{9 } -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-2 -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-4)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}+4](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B%5Csqrt%5B6%5D%7B8%7D%20%7D.%5Csqrt%7B2%7D-%28-%5Cfrac%7B18%7D%7B%5Csqrt%7B81%7D%20%7D%20-2%29%5C%5C%3D%5Cfrac%7B2%7D%7B%5Csqrt%5B6%5D%7B8%7D%20%7D.%5Csqrt%7B2%7D-%28-%5Cfrac%7B18%7D%7B9%20%7D%20-2%29%5C%5C%3D%5Cfrac%7B2%7D%7B%5Csqrt%5B6%5D%7B8%7D%20%7D.%5Csqrt%7B2%7D-%28-2%20-2%29%5C%5C%3D%5Cfrac%7B2%7D%7B%5Csqrt%5B6%5D%7B8%7D%20%7D.%5Csqrt%7B2%7D-%28-4%29%5C%5C%3D%5Cfrac%7B2%7D%7B%5Csqrt%5B6%5D%7B8%7D%20%7D.%5Csqrt%7B2%7D%2B4)
We can write ![\sqrt[6]{8}=(2^3)^{\frac{1}{6}}=(2)^{\frac{3}{6}}=2^\frac{1}{2}=\sqrt{2} \\](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B8%7D%3D%282%5E3%29%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%3D%282%29%5E%7B%5Cfrac%7B3%7D%7B6%7D%7D%3D2%5E%5Cfrac%7B1%7D%7B2%7D%3D%5Csqrt%7B2%7D%20%20%5C%5C)
Now, replacing ![\sqrt[6]{8}=\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B8%7D%3D%5Csqrt%7B2%7D)
![=\frac{2}{\sqrt[6]{8} }.\sqrt{2}+4\\=\frac{2}{\sqrt{2} }.\sqrt{2}+4\\=2+4\\=6](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%7D%7B%5Csqrt%5B6%5D%7B8%7D%20%7D.%5Csqrt%7B2%7D%2B4%5C%5C%3D%5Cfrac%7B2%7D%7B%5Csqrt%7B2%7D%20%7D.%5Csqrt%7B2%7D%2B4%5C%5C%3D2%2B4%5C%5C%3D6)
So, solving the expression
we get 6
Answer:
1927 times
Step-by-step explanation:
To do this, you divide the second value by the first value.
This gives us 188,869 divided by 98, which equals around 1927.
Hope this helps.
Use the compound interest formula
A = P (1 + r/n)^(nt).
Here A = unknown; B = initial amount = $300;
r = rate = 0.0218; n = 2 (2 compounding periods per year); and t = 1/2 (year).
Then A = $300 (1+0.0218/2)^(2*[1/2])
A = $300 (1.0218)^1 or A = $300(1.0218) = $306.54
hi
u0 = 64 with u(n+1) = un *0.75
u3 = 64 *0.75^3 = 27
sum is : 64 * ( 0.75^4 -1) / 0.75-1 = 175
manual proof : 64 + 48+36+27 = 175
Answer:
41.472 m²
8.449m²
Step-by-step explanation:
c) scale facot is 7.2/5 = 1.44
the square scale factor is 1.44^2 = 2.0736
times 20 by this to get the area
2.0737x 20 = 41.472 m²
d) 2.8/6 = SF = 0.467
0.2178 x 38.8 = 8.449m²