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san4es73 [151]
3 years ago
5

Find two consecutive integers such that the smaller integer is six more than twice the larger integer

Mathematics
1 answer:
ZanzabumX [31]3 years ago
8 0
Let the integers be x and x+1.

x = 6 + 2(x + 1)

x = 6 + 2x + 2

x = -8

Hence, the integers are -8 and -7.
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3 years ago
X2 (6x+ 1) (3x-9) = 0
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