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2 years ago

Stephan is having a fundraising and decides to sell some candy. He bought the box for $20, and

Mathematics

1 answer:

Flura [38]2 years ago

6 0

Answer: he would need to sell at least 41 candies to make a profit

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Use simple interest to find the interest and ending balance

hammer [34]

Answer:

Interest = $240

Ending Balance = $990

Step-by-step explanation:

Applying I = prt/100

= (750*4*8)/100

= 240

Therefore Interest = $240

Adding Interest to Principal

= $240 + $750 = $990

7 0

3 years ago

A toy store sold 405 dolls it sold equal number of dolls each month for 8 months and also sold a few extra dolls during the last

Simora [160]

Answer: 5 Extra dolls

Explanation: 400 divide by the 8 months equals 50 plus the 5 extra from 405

3 0

3 years ago

My number has 2 digits and is even, the sum of my numbers digits is 10, the difference of the two digits of my number is 6, my n

Stella [2.4K]

X + y = 10
x - y = 6
---------------add
2x = 16
x = 16/2
x = 8

x - y = 6
8 - y = 6
-y = 6 - 8
-y = -2
y = 2

number 82......factors of 82 are 1,2,4,82...so there are 4 factors

so ur number is 82 <==

8 0

3 years ago

please help i rly need it my math teacher gave me over 30 assignments and a project that are all due tomorrow today and i want t

Sedaia [141]

Answer:

x= -14

Step-by-step explanation:

-14 subtracted by 2 is -16, since its absolute it means its positive, meaning its 16 greater than 14, I may be wrong so just to let you know. Depends on how the teacher wants it to be.

8 0

2 years ago

The formula to find the period of orbit of a satellite around a planet is T^2=(4pi^2/GM)r^3 where r is the orbit's mean radius,

Natalija [7]

The answer is $r= \sqrt[3]{GMT^{2}/4 \pi^{2}}$

$T^{2} = \frac{4 \pi^{2}}{GM} r^{3}$

Move $\frac{4 \pi^{2} }{GM}$ to the other side of the equation:
$T^{2} /\frac{4 \pi^{2} }{GM} = r^{3} \\ 
T^{2} *\frac{GM}{4 \pi^{2} } = r^{3}$

Rearrange:
$r^{3} = T^{2} *\frac{GM}{4 \pi^{2} } \\ 
r^{3}= \frac{T^{2} *GM}{4 \pi^{2} } \\ 
r^{3}= \frac{GMT^{2}}{4 \pi^{2} } \\ 
r^{3} = GMT^{2}/4 \pi^{2}$

Since $x^{3}= \sqrt[3]{x}$ , then
$r^{3} = GMT^{2}/4 \pi^{2} \\ 
r= \sqrt[3]{GMT^{2}/4 \pi^{2}}$

3 0

3 years ago

Read 2 more answers