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3 years ago

Can some one help me idk what to do

Mathematics

2 answers:

Anna [14]3 years ago

8 0

9/10-(1/5+2/10)=
9/10-(2/10+2/10)=
9/10-4/10=5/10=
1/2

oksian1 [2.3K]3 years ago

7 0

The answer is 1/2. Hope this helps!

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Find the area of the figure. Round your answer to the nearest hundredth.

ASHA 777 [7]

$\bold{\huge{\underline{ Solution }}}$

<h3>Given :-</h3>

We have given one irregular figure which is composed of semicircle and parallelogram

We have to find the total area of the given irregular figure .

<h3>Let's Begin :-</h3>

We have, 

Semicircle having diameter = 8 in.
Therefore, R = 8/2 = 4 in.
Parallelogram having base and height 10 in. and 6 in.

We know that,

Area of semicircle

$\bold{\pink{ = }}{\bold{\pink{\dfrac{1}{2}}}}{\bold{\pink{\pi{r^{2}}}}}$

Subsitute the required values,

$\sf{ = }{\sf{\dfrac{22}{7}}}{\sf{\times{\dfrac{4^{2}}{2}}}}$

$\sf{ = }{\sf{\dfrac{22}{7}}}{\sf{\times{\dfrac{16}{2}}}}$

$\sf{ = }{\sf{\dfrac{22}{7}}}{\sf{\times{8}}}$

$\sf{ = }{\sf{\dfrac{176}{7}}}$

$\bold{ = 25.142\: in.^{2}}$

Area of parallelogram

$\bold{\red{ = Base }}{\bold{\red{\times{ Height }}}}$

Subsitute the required values,

$\sf{ = 10 }{\sf{\times{ 6 }}}$

$\bold{ = 60 \:in.^{2}}$

Thus, The area of parallelogram is 60 in.

<h3>Therefore, </h3>

Area of the given figure

= Area of semicircle + Area of parallelogram

Subsitute the required values,

$\sf{ = 25.142 + 60 }$

$\sf{ = 85.142\: in^{2}. }$

When round off to nearest Hundred

$\bold{ = 85.1 in.^{2}}$

Hence, The area of the given figure is 85.1 inches² .

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Answer:

Step-by-step explanation:

i got you its just D. <3

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The most used one would be a tree diagram

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321000759

Step-by-step explanation:

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3 years ago

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Supposed U = {-10, -9, -8, -7, -6, -5, -4, -3, -2, -1} is the universal set and K = {-10, -8, -6, -4, -2}. What is K’?

Ilia_Sergeevich [38]

Answer:

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Step-by-step explanation:

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3 years ago

Can some one help me idk what to do​

Can some one help me idk what to do