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Anna35 [415]
3 years ago
8

on a suspension bridge the roadway is hung from cables hanging between support towers. the cable of one bridge segment of the pa

rabola y=.1x^2-7x +150 where y is the height of the cable in feet above the roadway at the distance x feet from a support tower. what is the closest the cable comes to the roadway? how far from the support towers does this occur
Mathematics
1 answer:
Greeley [361]3 years ago
5 0
<span>The parabola opens upward and is symmetric to the y-axis. Its general form is: . y \;=\;ax^2 + c Its y-intercept is (0, 10) . . . Hence: . y \;=\;ax^2 + 10 It passes through (200, 100). We have: . 100 \:=\:a\cdot200^2 + 10 \quad\Rightarrow\quad a \:=\:\frac{9}{4000} Hence: . y \;=\;\tfrac{9}{4000}x^2 + 10 When x = \pm50,\;\;y \:=\:\tfrac{9}{4000}(50^2) + 10 \:=\:\frac{125}{8} Therefore, 50 feet from the center, the cable is 15\tfrac{5}{8} feet high.</span>
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In the diagram, p is the centroid of abc and pd = 3. find bd.
Anna35 [415]
We know that
if P is the centroid of triangle ABC
so
PD=(1/3)*BD
BD=3*PD-----> BD=3*3-----> BD=9 units

the answer is
BD=9 units
8 0
3 years ago
A scaled factor of 2 is used to increase the triangle. What is the new area?
lesya [120]

Answer:b

Step-by-step explanation:b

8 0
3 years ago
Which of the following could be the ratio between the lengths of the two legs of a 30-60-90 triangle?
Artist 52 [7]

Answer:c

options A  and B

Step-by-step explanation:

the ratio between the lengths of the two legs of a 30-60-90 triangle

General ration of 30-6- 90 degrees triangle is

x : xsqrt(3) : 2x

When x=1 the ratio becomes 1 : 1 sqrt(3)

when x= 2sqrt(3) the ratio becomes

It becomes

Two sides of 30-60-90 triangle cannot be equal

so option c  and option D are not possible

sqrt(2) is also not possible  because we have sqrt(3) in general ratio

PLS MARK ME AS BRAINLIEST.

5 0
1 year ago
X+y+z; use x=4, y=3, z=6
lubasha [3.4K]

Answer:

13

Step-by-step explanation:

x+y+z;

Let x=4, y=3, z=6

4+3+6

13

7 0
3 years ago
Read 2 more answers
express 121,200 in exponential (powers of 10) notation. express the earth sun distance in kilometers in powers of 10 notation.
Mashutka [201]

The exponential form of given number 121200 is 1.212 × 10^5

And the earth sun distance in kilometers in powers of 10 notation is 1.5 × 10^8

For given question,

We need to express 121,200 in exponential (powers of 10) notation.

To use scientific notation, pick a value between 1 and 10, then multiply it by 10ˣ.

The number between 1 and 10 in 121200 is 1.212 with 5 decimal points.

So, the exponential notation of given number would be,

121,200 = 1.212 × 10^5

Earth's average distance from the Sun is around 93 million miles (150 million kilometers). That's one AU.

So the number between 1 and 10 in 150,000,000 is 1.5, with 8 decimal points.

So, the distance between he Earth and the Sun is:

150,000,000 = 1.5 × 10⁸

Therefore, the exponential form of given number 121200 is 1.212 × 10^5

And the earth sun distance in kilometers in powers of 10 notation is 1.5 × 10^8

Learn more about the powers of 10 here:

brainly.com/question/13303295

#SPJ4

4 0
1 year ago
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