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Lady bird [3.3K]
4 years ago
12

I need these 2 questions answered please.​

Mathematics
1 answer:
Sav [38]4 years ago
5 0

The area of the circle is 28 ft square.

The area of the triangle is 30 ft square.

Step-by-step explanation:

1) The area of the circle= π*r^2

where π= 3.14(default value) and "r" is the radius of the circle.

Here, Radius of the circle(r)= 3 ft

Area = 3.14*3*3

        = 28.26 ft sq.= 28 ft sq(rounded to the nearest whole number)

2) The triangle has the base= 10 feet and height= 6 feet

The Area of the triangle= 1/2(b)(h)

where "b" is the base and "h" is the height of the triangle.

Substitute b=10 and h=6 ,

Area of triangle= 1/2(10 ft)(6 ft)= 60/2= 30 feet sq.

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The boys wrestling team scored a total of 36 points. Pins are worth 6 points. Major
shtirl [24]

Answer:

6p + 4d = 36

Step-by-step explanation:

If p = number of pins and d = number of major decisions, then the equation is 6p + 4d = 36.

Hope this helps!

5 0
3 years ago
Find the area of the shaded region in each of the following figure all unit are in cm
vodomira [7]
1st problem:
A = 630 cm


2nd problem:
A = 104 cm

All I can see on the picture you provided.
7 0
3 years ago
Which of the following is the simplest form of this expression?
Softa [21]

Step-by-step explanation:

which expression there is no expression here

4 0
3 years ago
A box has four cards numbered 1, 2, 3, and 4
lora16 [44]
Sample space: H1, H2, H3, H4, T1, T2, T3, T4
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I was unclear about the last two parts of the question.
6 0
3 years ago
Find cot theta if 180° < theta < 270° and cos theta = - sqrt 3/2
avanturin [10]

Answer:

cot theta = -√3

Step-by-step explanation:

we are given that  cos theta = - √3/2 within the range 180° < theta < 270° and

since cos theta = adj/hyp

adj = - √3

hyp = 2

Get the opposite using the pythagoras theorem

hyp^2 = opp^2 + adj^2

2² = opp² + (-√3)²

4 = opp² + 3

opp² = 4-3

opp² = 1

opp = 1

tan theta = opp/adj

tan theta = - 1/√3

Recall that cot theta = 1/tan theta

cot theta = 1/(-1/√3)

cot theta = -√3

8 0
3 years ago
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