Calculate the average rate of change of f(x) = x2 - 1 x - 4 for 2 ≤ x ≤ 6.

2 answers:

7 0

The average rate of change is (total change in f(x))/(total change in x) so

r=(f(6)-f(2))/(6-2)

r=(36-6-4-4+2+4)/4

r=7

Anna35 [415]3 years ago

4 0

Answer:

its 97/12

Step-by-step explanation:

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Find the area of the triangle. Enter your answer in the box.

BlackZzzverrR [31]

The answer is 12 m2
Explanation:

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2 years ago

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Equation M: y = 3x + 4

solmaris [256]

Y = 3x + 4
y = 3x + 7

3x + 4 = 3x + 7
3x - 3x = 7 - 4
0 = 3.....incorrect....this system has no solutions because ur lines are parallel and they never cross.

or look at it this way..
y = 3x + 4
y = 3x + 7

both have slopes of 3...but the y intercepts are different......when this happens, it means the lines are parallel with no solution

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3 years ago

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Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimeters,

tiny-mole [99]

Answer:

Probability that the sample mean would be greater than 141.4 millimetres is 0.3594.

Step-by-step explanation:

We are given that Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimetres, and a standard deviation of 7.

A random sample of 39 steel bolts is selected.

Let $\bar X$ = sample mean diameter

The z score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }$ ~ N(0,1)

where, $\mu$ = population mean diameter = 141 millimetres

$\sigma$ = standard deviation = 7 millimetres

n = sample of steel bolts = 39

Now, Percentage the sample mean would be greater than 141.4 millimetres is given by = P( $\bar X$ > 141.4 millimetres)

P( $\bar X$ > 141.4) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }$ > $\frac{141.4-141}{\frac{7}{\sqrt{39} } } }$ ) = P(Z > 0.36) = 1 - P(Z $\leq$ 0.36)