Answer:
the answer is 19-2v combine like terms if not that then try this....
19-2y=0
-2y=-19
Then divide by -2
y=-19/-2
=9.5
Answer:
a.P.I=
b.G.S=
Step-by-step explanation:
We are given that a linear differential equation

We have to find the particular solution
P.I=
P.I=
P.I=
P.I=
(higher order terms can be neglected
P.I=
b.Characteristics equation


C.F=
G.S=C.F+P.I
G.S=
Answer:
4x-y+1=0
Step-by-step explanation:
here,given equation of a line id
4x-y-2=0.. eqn(i)
equation of any line parallel to line (i) is
4x-y+k=0...eqn(ii)
since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]
4*1-5+k=0
or, 4-5+k=0
or,-1+k=0
•°•k=1
substituting the value of k=1 in eqn(ii),
4x-y+1=0 is the required equation of the line.
Answer:
The answer is 16, I am pretty sure.
Step-by-step explanation:
I am soo sorry if it is wrong.