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kati45 [8]
3 years ago
8

What is common difference between successive terms in the sequence? 2,8,14,20,26

Mathematics
2 answers:
aniked [119]3 years ago
6 0
The difference is 6. Each number increases by 6 in the sequence.
2 + 6 = 8
8 + 6 = 14
14 + 6 = 20
20 + 6 = 26
Etc.
I would really appreciate it if I could get brainliest. Thanks!! =D
Ugo [173]3 years ago
4 0
The difference between the numbers is the gap of 6, it goes from 2 to 8 (6 numbers were skipped) , then it went from 8 to 14 (6 numbers were skipped once again) , and etc etc. 
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Select two ratios that are equivalent to 4:18
steposvetlana [31]

Answer:

2:9

Step-by-step explanation

4:18 divided by 2 is the lowest it can go so 4 divided by 2 is 2

18 divided by 2 is 9 so,

2:9

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3 years ago
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You are in a hot air balloon looking down at two ponds. Pond A which is in front of your balloon, is at an angle of depression t
MatroZZZ [7]

a. See attachment for the labelled diagram

b. Using the sine ratio, distance from the hot air to pond A is 5,038.9 m, while distance from the hot air to pond B is 6,287.1 m.

c. Distance between the two ponds is 1,263.5 m.

<h3>What is the Sine and Tangent Ratios?</h3>

Sine ratio, is: sin ∅ = opposite side/hypotenuse length

Tangent ratio is: tan ∅ = opposite side/adjacent length.

a. The diagram with the appropriate labels is shown in the image attached below.

b. Use the sine ratio to find the distance from the hot air to pond A (CA) and to pond B (CB):

CA = hypotenuse

∅ = 10°

Opposite = 875 m

sin 10 = 875/CA

CA = 875/sin 10

CA ≈ 5,038.9 m (distance from the hot air to pond A)

CB = hypotenuse

∅ = 8°

Opposite = 875 m

sin 8 = 875/CB

CB = 875/sin 8

CB ≈ 6,287.1 m (distance from the hot air to pond B)

c. Distance between the two ponds, BA = BD + DA.

Apply the tangent ratio to find BD and DA

tan 8 = 875/BD

BD = 875/tan 8

BD = 6,225.9 m

tan 10 = 875/DA

DA = 875/tan 10

DA = 4,962.4 m

Distance between the two ponds = 6,225.9 - 4,962.4 = 1,263.5 m.

Learn more about the sine and tangent ratios on:

brainly.com/question/24137232

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8 0
2 years ago
The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per
ICE Princess25 [194]

Answer:

1.76% probability that in one hour more than 5 clients arrive

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per hour.

This means that \mu = 2

What is the probability that in one hour more than 5 clients arrive

Either 5 or less clients arrive, or more than 5 do. The sum of the probabilities of these events is decimal 1. So

P(X \leq 5) + P(X > 5) = 1

We want P(X > 5). So

P(X > 5) = 1 - P(X \leq 5)

In which

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353

P(X = 1) = \frac{e^{-2}*2^{1}}{(1)!} = 0.2707

P(X = 2) = \frac{e^{-2}*2^{2}}{(2)!} = 0.2707

P(X = 3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1804

P(X = 4) = \frac{e^{-2}*2^{4}}{(4)!} = 0.0902

P(X = 5) = \frac{e^{-2}*2^{5}}{(5)!} = 0.0361

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1353 + 0.2702 + 0.2702 + 0.1804 + 0.0902 + 0.0361 = 0.9824

P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9824 = 0.0176

1.76% probability that in one hour more than 5 clients arrive

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