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jeka94
3 years ago
10

The face of a clock has a circumference of 63 in what is the area of the face of the clock​

Mathematics
1 answer:
Rudik [331]3 years ago
7 0
Answer: 5 ft 3 in I believe.
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SOMEONE PLEASEEEEE HELP .... GIVING BRAINILEST!!!
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Answer: Value of M: -49

Value of N: 24

Step-by-step explanation:

Yw and pls mark me brainiest

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The two-way table below shows an intendant careers among an incoming class of first-year college students, divided by gender. If
vovangra [49]

Step-by-step explanation:

If one student is chosen from a pool of 2444 maie students, of which 102 are aspiring research scientists, the probability that the chosen student student is a future research scientist is

102/2444 = 4.17% (to the nearest hundredth percent)

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(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0
Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

P(A)+P(B)+P(A\cap B)=P(A\cup B)

We know that

Maximum value of P(A\cup B)=1 and minimum value of P(A\cup B)=0

0\leq P(A\cup B )\leq 1

0\leq P(A)+P(B)-P(A\cap B)\leq 1

0\leq 0.4+0.7-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)

P(A\cap B)\leq 1.1

It is not possible that P(A\cap B) is equal to 1.1

1.1-P(A\cap B)\leq 1

-P(A\cap B)\leq 1-1.1=-0.1

Multiply by (-1) on both sides

P(A\cap B)\geq 0.1

Again, P(A\cup B)\geq P(B)

0.4+0.7-P(A\cap B)\geq 0.7

1.1-P(A\cap B)\geq 0.7

-P(A\cap B)\geq -1.1+0.7=-0.4

Multiply by (-1) on both sides

P(A\cap B)\leq 0.4

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3 years ago
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Probability=(number of specific outcomes)/(number of possible outcomes)

There are 4+2+6+5=17 total marbles so:

P(Yellow)=4/17

P(Blue)=2/17

P(Black)=5/17

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Xelga [282]

Answer:

y = 0.6x

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m = (1.2 - 0)/(2 - 0)

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m = 0.6

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