The present age of father is 86 years old and present age of son is 48 years old
<em><u>Solution:</u></em>
Given that, a father is now 38 years older than his son
Ten years ago he was twice as old as his son
Let "x" be the age of son now
Therefore, from given,
Father age now = 38 + age of son now
Father age now = 38 + x
<em><u>Ten years ago he was twice as old as his son</u></em>
Age of son ten years ago = age of son now - 10
Age of son ten years ago = x - 10
Age of father ten years ago = 38 + x - 10
Then we get,
Age of father ten years ago = twice the age of son ten years ago
38 + x - 10 = 2(x - 10)
28 + x = 2x - 20
2x - x = 28 + 20
x = 48
Thus son age now is 48 years old
Father age now = x + 38 = 48 + 38 = 86
Thus present age of father is 86 years old and present age of son is 48 years old
Combine the like terms
-x-x^2+7
Answer:
x + 10 = 4x
Step-by-step explanation:
Let x = her age 10 years ago.
Her age now is x + 10.
x + 10 = 4x
Answer:
J=-50
Step-by-step explanation:
Analyzing the given values and the given equation, we have the following:
A = $25,000
r = 0.11
t = 6
The equation has the form:
y = A (1-r)^t
Plugging in the given values into the equation,
y = $25,000 (1 - 0.11)^6
y = $25,000 (0.89)^6
Therefore, the answer is
A. y=25,000(.89)^6
