Question

Determine g(-1) for g(t)=(t^2-1)(t+4) A)-2 B)-6 C)3 D)0

Answer 1

It is C because Since {{g(x)}={x^3+2}}g(x)=x​3​​+2g, left parenthesis, x, right parenthesis, equals, x, start superscript, 3, end superscript, plus, 2, we can substitute {x^3+2}x​3​​+2x, start superscript, 3, end superscript, plus, 2 in for {g(x)}g(x)g, left parenthesis, x, right parenthesis.\begin{aligned}{f(g(x))}&=3(g(x))-1 \\\\ &=3({x^3+2})-1 \\\\ &=3x^3+6-1\\\\ &=3x^3+5 \end{aligned}​f(g(x))​​​​​​​​​=3(g(x))−1​=3(x​3​​+2)−1​=3x​3​​+6−1​=3x​3​​+5​​

Answer 2

D option that is 0 will be answer