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Vlad [161]
3 years ago
7

Which factor explains why coal dust in an enclosed space is more explosive than coal dust blown outdoors into an open space ? A.

Temperature.
B.surface area
C.concentration
D.Volume
E.catalyst
Chemistry
2 answers:
ZanzabumX [31]3 years ago
8 0

The correct option is B.

Coal dust refers to the powered form of coal. Because of the high surface area of coal dust it is highly prone to dust explosion, which involves rapid combustion of fine particles that are suspended in the air; this usually occur in an enclosed place. Coal dust in an enclosed place is more explosive than coal dust that is blown outdoor in an open space because the coal dust in an enclosed place is more concentrated due to restricted space, thus it is more liable to explosion.

Amanda [17]3 years ago
5 0
C.concentration.much more explosive in a contained area.
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lubasha [3.4K]

Ans 1. Both

Ans 2. Once inside plants, carbon moves through food chains, where organisms become nutrients including herbivores, carnivores and ultimately, decomposers. Once buried in the soil, carbon can be converted into fossil fuels over long periods of time and then also reenter the atmosphere by combustion. The Law of Conservation of Matter states that matter cannot be created or destroyed. The carbon cycle is an example of the Law

Ans 3. Most of the chemical energy needed for life is stored in organic compounds as bonds between carbon atoms and other atoms. The law of conservation of energy states that energy can not be created or destroyed. Thus, just like matter energy is also conserved in the process.

Hope it helps

3 0
4 years ago
15.0 mL of 0.050 M Ba(NO3)2 M and 100.0 mL of 0.10 M KIO3 are added together in a 250 mL erlenmeyer flask. In this problem, igno
timama [110]

Answer:

Yes, precipitation of barium iodate will occur.

Explanation:

Molarity of barium nitrate solution = 0.050 M

Volume of barium nitrate solution =15.0 mL = 0.0150 L

1 mL = 0.001 L

Moles of barium nitrate = n

n=0.050 M\times 0.0150L=0.00075 mol

Ba(NO_3)_2(aq)\rightarrow Ba^{2+}(aq)+2NO_3^{-}(aq)

Moles of barium ions: 1\times 0.00075 mol=0.00075 mol

Molarity of potassium iodate solution = 0.10 M

Volume of potassium iodate solution =100.0 mL = 0.1000 L

1 mL = 0.001 L

Moles of potassium iodate = n'

n'=0.10 M\times 0.1000 L=0.01 mol

KIO_3(aq)\rightarrow K^{+}(aq)+IO_3^{-}(aq)

Moles of iodate ions = 1\times 0.01 mol=0.01 mol

After mixing of both solution in 250 mL in erlenmeyer flask

Volume of the final solution = 250 mL = 0.250 L

Concentration of barium ions in 250 mL solution :

[Ba^{2+}]=\frac{0.00075 mol}{0.250 L}=0.003 M

Concentration of iodate ions:

[IO_3^{-}]=\frac{0.01 mol}{0.250 L}=0.04 M

Solubility product of barium iodate,K_{sp}=4.01\times 10^{-9}

Ionic product of the barium iodate in solution :K_i

Ba(IO_3)_2\rightleftahrpoons Ba^{2+}+2IO_3^{-}

K_i=[Ba^{2+}][IO_2^{-}]^2

K_i=0.003 M\times (0.04 M)^2=4.8\times 10^{-6}

K_{sp}  ( precipitation)

As we can see, the ionic product of the barium iodate is greater than the solubility product of the barium iodate precipitation of barium iodiate will occur in 250 mL of final solution.

5 0
3 years ago
How many moles of PCl5 can be produced from 53.0 g of Cl2 (and excess P4)?
elena55 [62]

Answer:

0.299 moles of PCl5

Explanation:

First form an equation based of given information: P4 + Cl2= 4PCl5

Next balance it: P4 + 10Cl2 = 4PCl5

Take your given value (53.0g of Cl2) and divide it by its molar mass to get moles of Cl2: 53.0g/70.906g = 0.747 moles Cl2

Then, multiply by the molar ratio (10Cl2 to 4PCl5): (0.747 x 4 mol PCl5)/10 mol Cl2 = 0.299 moles PCl5

5 0
3 years ago
Which of the following elements in group 1 of the periodic table has the smallest atomic radius?
ivann1987 [24]
The element in group 1 of the periodic table that had the smallest atomic radius is A. Lithium.
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3 years ago
How can you predict an elements group and period
mina [271]
Who cares about this question
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