Rutherford's experiment was the gold foil experiment.
The gold foil experiment was him shooting alpha particles (you could think of this as a Helium atom without its electrons) into a gold foil. The whole experiment was surrounded with something called Zinc Sulfide which sparked when the alpha particles hit it.
Most of the alpha particles went through, approximately 1 in 8000 alpha particles deflected at a large angle (almost right back to where it was shot).
This constant ratio caused him to conclude that:-the atom was mostly empty space (since most alpha particles went through)-there was something very positive in the atom (the proton)-the proton was very dense (since it made something going light speed deflect back at a large angle)-The proton was also very small (since only 1 in 8000 hit it)
Prior to the discovery of the proton, John Dalton's periodic table was used. Having "elements" such as soda and potash. Now that we have discovered the proton and found out that each atom's number of protons is unique, we used that to classify each element's identity.
Answer:
Explanation:
1. Energy balance
By the first law of thermodynamics, considering the system is closed and isolated, the heat released by the 237 g piece of molybdenum equals the heat absorbed by the 244 g of water.
2. Heat equation
The heat released or absorbed by a substance is proportional to the product of the mass, the specific heat and the change in temperature
3. Heat released by the 237 g piece of molybdenum
At equilibrium:
- Q₁ = 237 g × C × (100.0ºC - 15.3ºC)
4. Heat absorbed by the 244 g of water
At equilibrium:
- Q₂ = 244 g × 4.184 J/gºC × (15.3ºC - 10.0ºC)
5. Solve for C from Q₁ = Q₂
- 237 g × C × (100.0ºC - 15.3ºC) = 244 g × 4.184 J/gºC × (15.3ºC - 10.0ºC)
- 20,073.9 × C = 5,410.7488 J/gºC
The result must be reported with 3 significant figures: C = 0.270 J/gºC.
Answer:
Explanation:
Hope this helps:
AgOH is silver hydroxide
HF is hydrofluoric acid
NiOOH is nickel oxide hydroxide
NH4OH is ammonium hydroxide
HMnO4 is Permanganic acid
Zn(OH)2 is zinc hydroxide
Answer:
The correct answer is 4 substracting hydride ions from olefins.
Explanation:
The olefins are the unsaturated hydrocarbon also called alkenes that contain one double bond present between 2 carbon atoms.
On the other hand a carbenium ion is formed when a hydrocarbon loses a hydride ion to form a positively charged product.
For example allyl cation
CH2=CH-CH2+
The allyl cation is a carbenium ion formed by the removal of H- ion or hydride ion from the alkene propene.
