Explanation:
The given data is as follows.
Flow of chlorine (Q) = 
Amount of liter present per day is as follows.

It is given that dosage of chlorine will be as follows.
10 mg/l =
kg/l
Therefore, total chlorine requirement is as follows.
Total chlorine requirement =
kg/day
= 100 kg/day
Thus, we can conclude that the kilograms of chlorine used daily at the given water treatment plant is 100 kg/day.
Answer: Mass in an object is often weighed on a scale. The standard units used to measure mass are the grams (g) and kilogram (kg).
To calculate the density of an object you use the density formula which is:
D=m/v
now we plug in what we're given.
m=25.0g
v=49.10mL-45.50mL=3.6mL
D=25.0g/3.6mL=6.9 g/mL
The density of the iron is 6.9 g/mL. (btw, I left the answer in significant figures)
Answer:
47
Explanation:
Let's consider the following reaction at equilibrium.
H₂(g) + I₂(g) ⇌ 2 HI(g)
The concentration equilibrium constant (Kc) is the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients.
Kc = [HI]² / [H₂] × [I₂]
Kc = (1.6)² / 0.14 × 0.39
Kc = 47