An increase in temperature at constant volume will increase the kinetic energy and the distance. Thus, option c is correct.
<h3>What is Gay-Lussac's law?</h3>
Gay-Lussac's law is the ideal gas law that defines the direct relation of the temperature to the pressure of the gas at a constant volume.
With an increase in the temperature of the gas, the pressure also rises causing the distance between the particle to expand by the increase in the kinetic energy.
Therefore, option c. the kinetic energy, particle distance, and the pressure increases with tempearture rise.
Learn more about Gay-Lussac's law here:
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Answer:
See below.
Step-by-step explanation:
An incandescent lamp produces all colours of the visible spectrum, with wavelengths ranging from approximately 400 nm (violet) to 700 nm (red).
Since <em>energy is inversely proportional to wavelength</em>,
E ∝ 1/λ
a quantum of 400 nm violet light has more energy than one of 700 nm red light.
An incandescent lamp produces a relatively small amount of the high-energy blue/violet light
( see image below).
The table below gives the colours in the visible spectrum, ranked from highest to lowest energy.
<u>Colour λ/nm </u>
Violet 400 – 450
Blue 450 – 490
Cyan 490 – 520
Green 520 – 560
Yellow 560 – 590
Orange 590 – 635
Red 635 – 700
Answer: 367 grams
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number
of particles.
Enthalpy of vaporization is the amount of heat released when 1 mole of substance is converted from liquid to gaseous state.
Given : Enthalpy of vapourization of
= 17.4 kJ/mol
To calculate the number of moles, we use the equation:


1 mole of
produces heat = 17.4 kJ
8.3 moles of
produces heat = 
Given : Enthalpy of vapourization of
= 6.0 kcal/mol =
(1kcal=4.184kJ)
25.104 kJ heat is produced by = 1 mole of
144 kJ heat is produced by =
of
Mass of 
Thus 367 grams of
must be evoparated o remove as much heat as evaporation of 1.00 kg of 