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3 years ago

Why is one side of the moon called "the dark side of the moon"?

1 answer:

4 0

The 'dark side' of the Moon refers to the hemisphere of the Moon that is facing away from the Earth. ... It is only 'dark' to us, as that hemisphere can never be viewed from Earth due to a phenomenon known as 'Tidal Locking'

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In general the state of matter with the most energy is ?

CaHeK987 [17]

Gas

Gas particles got the most energy because of how freely the molecules move

Hope this helped you, have a good day bro cya)

8 0

3 years ago

Read 2 more answers

Gas molecules colliding with the walls of a container exert a force called ___

ANTONII [103]

I believe this force would be called pressure!

6 0

3 years ago

Generally speaking, which group would have the lowest electronegativity values in a period?

dezoksy [38]

Answer: Group 1 would have the lowest electronegativity values.

Explanation:

Electronegativity is the power of an atom in a molecule to attract electrons. It is also synonymous with the oxidizing ability or non-metallic character of elements.

Generally, across a given period from left to right, electronegativity increases due to increasing nuclear charge and decreasing atomic radius ( or atomic size ). This is because there is a greater tendency for a smaller atom with higher nuclear attraction to attract electrons than a larger atom with a lower nuclear attraction due to the shielding effect of the nuclear attraction by the inner shell electrons on the outermost electrons in the larger atom.

Also, down a particular group, electronegativity generally decreases due to increasing atomic radius/size.

This is why metals are generally electropositive ( lose electrons ) and non-metals are electronegative ( gain electrons ) as they are both found more on the left and right sides of the periodic table respectively.

3 0

3 years ago

Read 2 more answers

Write a chemical equation depicting what happens to the sugar in water.

zysi [14]

Assuming that you mean table sugar (sucrose), then at room temperature and without any catalyst, there is no reaction.

However if you elevate and hold the temperature of the aqueous solution at 50 to 60 °C (especially in the presence of a suitable catalyst, like mineral acid) the sucrose dimer will split into glucose and fructose. This is called hydrolysis and the resulting solution is called an invert sugar solution.

The reaction could be written as:

C12H22O11 (sucrose) + H2O (water) → C6H12O6 (glucose) + C6H12O6 (fructose)

or

C12H22O11 (aq) + H2O (l) → C6H12O6 (aq) + C6H12O6 (aq)

Notice that both of the produced sugars have the same empirical formula. Check with your instructor or in your textbook to see if more exact formulas are needed.

5 0

3 years ago

Estimate ΔH for the reaction: C2H6(g) + Cl2(g)--> C2H5Cl(g) + HCl(g) given the following average bond energies (in kJ/mol): C

Leno4ka [110]

Explanation:

The reaction equation will be as follows.

$C_{2}H_{6}(g) + Cl_{2}(g) \rightarrow C_{2}H_{5}Cl(g) + HCl(g)$

Using bond energies, expression for calculating the value of $\Delta H$ is as follows.

$\Delta H = \sum B.E_{reactants} - \sum B.E_{products}$

On reactant side, from $C_{2}H_{6}$ number of bonds are as follows.

C-C bonds = 1

C-H bonds = 6

From $Cl_{2}$ ; Cl-Cl bonds = 1

On product side, from $C_{2}H_{5}Cl$ number of bonds are as follows.

C-C bonds = 1

C-H bonds = 5

C-Cl bonds = 1

From HCl; H-Cl bonds = 1

Hence, using the bond energies we will calculate the enthalpy of reaction as follows.

$\Delta H = \sum B.E_{reactants} - \sum B.E_{products}$

= $[(1 \times 348 kJ/mol) + (6 \times 414 kJ/mol) + (1 \times 242 kJ/mol)] - [(1 \times 348 kJ/mol) + (5 \times 414 kJ/mol) + (1 \times 327 kJ/mol) + (1 \times 431 kJ/mol)]$ = -102 kJ/mol

Thus, we can conclude that change in enthalpy for the given reaction is -102 kJ/mol.

5 0

3 years ago