Answer:
139
Step-by-step explanation:
(5*8)+(9*11)
40+99
139
The value would be 829.89.
The formula we use is

,
where A is the total amount, p is the principal, r is the rate expressed as a decimal number, n is the number of times per year the interest is compounded, and t is the number of years.
We will use 800 for p; 5.25/100 = 0.0525 for r; 365 for n; and (255/365) for t (since it is not a full year):
Answer:
Step-by-step explanation:
The null hypothesis is:
H0: μ(1995)=μ(2019)
The alternative hypothesis is:
H1: μ(1995)<μ(2019)
Because Roger wants to know if mean weight of 16-old males in 2019 is more than the mean weight of 16-old males in 1995 the test only uses one tail of the z-distribution. It is not a two-sided test because in that case the alternative hypothesis would be: μ(1995)≠μ(2019).
To know the p-value, we use the z-statistic, in this case 1.89 and the significance level. Because the problem does not specify it, we will search for the p-value at a 5% significance level and at a 1%.
For a z of 1.89 and 5% significance level, the p-value is: 0.9744
For a z of 1.89 and 1% significance level, the p-value is: 0.9719