Answer:
- 8 3/4
- 2, 3
- 4 1/2, 11 1/4
- 9 3/4, 16 1/4
- Y/B = 2/3
Step-by-step explanation:
<h3>a)</h3>
The first line is simply the sum of the two given numbers.
3 1/2 +5 1/4 = (3+5) +(2/4+1/4) = 8 3/4
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To find values on the remaining lines, it is convenient to find the ratios of the numbers involved. The ratio of yellow to blue is ...
Y/B = (3 1/2)/(5 1/4) = (7/2)/(21/4) = (7/2)(4/21) = 2/3
Then ...
Y : B : total = 2 : 3 : 5
This tells you the numbers on the second line are ...
Y = 2; B = 3
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The value for B on the third line is the basic ratio number multiplied by (6 3/4)/3 = 2 1/4. Then the other two numbers are ...
Y = 2(2 1/4) = 4 1/2
total = 5(2 1/4) = 11 1/4
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The value for Y on the fourth line is the basic ratio number multiplied by (6 1/2)/2 = 3 1/4. Then the other two numbers are ...
B = 3(3 1/4) = 9 3/4
total = 5(3 1/4) = 16 1/4
_____
<h3>b)</h3>
The equation is the one we used to find the values on the second line:
Y/B = 2/3
Well, I know to find the mean you add all the numbers and divide it by how many numbers there were, so I'm guessing you just do that with the stem and leaf plot. I hoped this helped a bit
Answer:
w=9
Step-by-step explanation:
Our equation is: 8w-15=57
Add 15 to both sides
-15 is now gone because we added 15 so it would be zero
and we have 72 because 15 plus 57 is 72
Now we have:
8w=72
Divide by 8 on both sides
8w cancels out to just w
and 72 divided by 8 is 9
And you're left with:
w=9
Answer:
D. Rx) = x2 - 4x + 10
Step-by-step explanation:
R(x)=(x-2)^2+6
R(x)=(x-2)^2+6
=(x-2)(x-2)+6
=x^2-2x-2x+4+6
=x^2-4x+10
R(x) = x^2 - 4x + 10
Option D is the answer
Question 11a)
We are given side BC equals to side CE and angle CBA equals to angle CED
We also know that angle ACB equals to angle ECD are equal (opposite angles properties)
We have enough information to deduce that triangle ABC and triangle CDE are equal by postulate Angle-Side-Angle (ASA)
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Question 11b)
We are given side AB equal to side ED, side BC equals to side EF, and side AC equals to side DF
We have enough information to deduce that triangle ABC and triangle DEF congruent by postulate Side-Side-Side (SSS)
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Question 11c)
We are given side AC equals to side DF, angle ABC equals to angle DEF, and angle BAC equals to angle EDF
We have enough information to deduce that triangle ABC congruent to triangle DEF by postulate Angle-Side-Angle (ASA)
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Question 11d)
We do not have enough information to tell whether this shape congruent or not
