In trapezoid ABCD with bases AB and DC , diagonals intersect at point O. Find the length of diagonal BD , if BO=6 cm and: AO/AC
1 answer:
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So you want to solve for x?
It would be nice if this would easily factor:
(-4x + 5)(2x +1) = 0 This will not work!
So you need to use the quadratic formula:
a = -8, b = 4, c = 5
x = (-4 +/-
)/2(-8)
= (-4 +/-
)/-16
= (-4 +
)/-16
= 1/4 -
/4
It would be nice if this would easily factor:
(-4x + 5)(2x +1) = 0 This will not work!
So you need to use the quadratic formula:
a = -8, b = 4, c = 5
x = (-4 +/-
= (-4 +/-
= (-4 +
= 1/4 -
The picture in the attached figure
we know that
m ∠ 6=123.5°
m ∠6+m∠2=180°-------> by supplementary angles
so
m∠2=180-m∠6-----> 180-123.5------> m∠2=56.5°
m∠1=m∠2--------> by corresponding angles
so
m∠1=56.5°
the answer is
m∠1 is 56.5°
we know that
m ∠ 6=123.5°
m ∠6+m∠2=180°-------> by supplementary angles
so
m∠2=180-m∠6-----> 180-123.5------> m∠2=56.5°
m∠1=m∠2--------> by corresponding angles
so
m∠1=56.5°
the answer is
m∠1 is 56.5°