Ask question

Ask question

All categories

2 years ago

8

Use the distributive property to find the product

1 answer:

storchak [24]2 years ago

5 0

Answer:

14mn-12m

Step-by-step explanation:

You might be interested in

Given the piecewise function shown below , select all of the statements that are true.

TEA [102]

Shown Where? You didnt add a picture of a graph

4 0

2 years ago

Dhanraj spent $204.20 purchasing volleyballs and basketballs.

Lemur [1.5K]

Answer:

Number of volleyballs bought = 8

Number of basketballs bought = 11

Step-by-step explanation:

Given that:

Total amount spent = $204.20

Let,

x be the number of volleyballs

y be the number of basketballs

According to given statement;

y = x+3 Eqn 1

8.20x+12.60y=204.20 Eqn 2

Putting value of y from Eqn 1 in Eqn 2

8.20x + 12.60(x+3) = 204.20

8.20x + 12.60x + 37.80 = 204.20

20.80x = 204.20 - 37.80

20.80x = 166.40

Dividing both sides by 20.80

$\frac{20.80x}{20.80}=\frac{166.40}{20.80}\\x=8$

Putting x=8 in Eqn 1

y = 8+3 = 11

Hence,

Number of volleyballs bought = 8

Number of basketballs bought = 11

6 0

2 years ago

Which box plot represents data that contains an outlier?

boyakko [2]

Answer:

It is C

Step-by-step explanation:

hope it help

6 0

2 years ago

Read 2 more answers

Identify one pair of vertical angles in the diagram below,

pshichka [43]

Angle b and d the third option

4 0

1 year ago

Read 2 more answers

B) Mrs. Shakya sold a jewellery at a loss of 5%. If she had sold it at Rs 5,200 more,

Nadusha1986 [10]

Answer:

$\huge{ \fbox{ \sf{Rs \: 40000}}}$

Step-by-step explanation:

$\sf{Let \: CP \: ( \: cost \: price) \: be \: x}$

$\sf{Loss \: \% \: = 5 \% \: }$

$\sf{Selling \: price = CP \: - \: loss \: \% \: of \: CP}$

$\mapsto{ \sf x - \frac{5}{100} \times x}$

$\mapsto{ \sf{x - \frac{x}{20} }}$

$\mapsto{ \sf{ \frac{x \times 20 - x}{20} }}$

$\mapsto{ \sf{ \frac{20x - x}{20}}}$

$\mapsto{ \sf{ \frac{19x}{20}}}$

Now, Finding the New selling price

$\sf{New \: SP \: ( \: selling \: price)} = \frac{19x}{20} + 5200$

$\mapsto{ \sf{ \frac{19x + 5200 \times 20}{20}}}$

$\mapsto{ \sf{ \frac{19x + 10400}{20}}}$

Finally, finding the Cost price :

We have, Profit % = 8 %

$\sf{Cost \: price = Selling \: price \: - \: P\% \: of \: CP}$

$\mapsto{ \sf{x = \frac{19x + 104000}{20} - 8\% \: of \: x}}$

$\mapsto{ \sf{x = \frac{19x + 104000}{20} - \frac{8x}{100} }}$

$\mapsto{ \sf{x = \frac{19x + 104000}{20} - \frac{2x}{25} }}$

$\mapsto{ \sf{x = \frac{5(19x + 104000) - 2x \times 4}{100} }}$

$\mapsto{ \sf{x = \frac{95x + 520000 - 8x}{100} }}$

$\mapsto{ \sf{x = \frac{87x + 520000}{100}}}$

$\mapsto{ \sf{100x = 87x + 520000}} \: \: ( \sf{Cross \: multiplication}$

$\mapsto{ \sf{100x - 87x = 520000}}$

$\mapsto{ \sf{13x = 520000}}$

$\mapsto{ \sf{x = \frac{520000}{13}}}$

$\mapsto{ \boxed {\sf{x = 40000}}}$

Therefore, the cost price of the jewellery is Rs 40000

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

5 0

2 years ago