Question

The first tap can fill the pool in 10 hours. When the second tap was opened, the empty pool was filled in 6 hours. How long will it take the second tap to fill the pool alone?

Answer 1

Answer:

15 hours

Step-by-step explanation:

We can use the formula below to solve this:

$\frac{t}{x}+\frac{t}{y}=1$

Where

t is the time taken for BOTH to fill up the pool [6 hours]

a is the time taken by first tap [10 hours]

b is the time taken by second tap [we need to find this]

Now putting in all the into and solving for y, we get:

$\frac{t}{x}+\frac{t}{y}=1\\\frac{6}{10}+\frac{6}{y}=1\\\frac{6}{y}=1-\frac{6}{10}\\\frac{6}{y}=\frac{2}{5}\\2y=30\\y=15$

Hence, its gonna take 15 hours for the second tap to fill the pool alone.