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3 years ago

Karina is showing her steps to solve the expression −26.7 ÷ 1/3

Mathematics

2 answers:

timama [110]3 years ago

6 0

Step 2: -26.7 · -3

When you divide with a fraction, it's helpful to multiple by the reciprocal of the fraction .

This step instead multiplied by the negative reciprocal .

Therefore, the correct answer would be -80.1 instead of 80.1

The error was made in step 2.

sashaice [31]3 years ago

6 0

Answer: Step 2! I took the test!!

Step-by-step explanation:

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Dima020 [189]

Answer:

17.5 for perpendicular triangle

Step-by-step explanation:

A= 1/2 ( b*h )

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A= 1/2 ( 35)

A= 17.5

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2 years ago

I cannot figure this problem out

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Answer:

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Step-by-step explanation:

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3 years ago

What is the answer to 2(9x+12) A.18x+12 B.18x+24 C.9x+24

LUCKY_DIMON [66]

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3 years ago

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Someone do as much of the page as possible (ill mark brainlyless)

Sindrei [870]

Answer:

Step-by-step explanation:

1) a² - b² = (a + b)(a- b)

2) a³ + b³ = a³ + 3a²b + 3ab² + b³

3) a³ - b³ = a³ - 3a²b + 3ab² - b³

5) x⁴ - 36 = (x²)² - 6² = (x² + 6) (x² - 6)

6)64c³ + 1 = (4c)³ + 1³ = (4c)³ + 3(4c)²(1) + 3(4c)(1)³ + 1³

= 64c³ + 3(16c²) + 12c +1

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7) k³ - 27 = k³- 3³ = (k + 3)(k - 3)

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2 years ago

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Find two rational expressions a / b and c / d that produce the result x − 1 / x2 when using the following operations. Answers

Mars2501 [29]

Answer:

a) Let $\frac{a}{b}=\frac{-1}{x^2}, \text{ and } \frac{c}{d}=\frac{1}{x}$ .

Observe that

$\frac{a}{b}+\frac{c}{d}=\frac{-1}{x^2}+\frac{1}{x}=\frac{-x+x^2}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x^2}.$

Observe that

$\frac{a}{b}-\frac{c}{d}=\frac{1}{x}-\frac{1}{x^2}=\frac{x^2-x}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x}.$

Observe that

$\frac{a}{b}*\frac{c}{d}=\frac{x-1}{x}*\frac{1}{x}=\frac{(x-1)1}{x*x}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{x}{1}.$

Observe that

$\frac{a}{b}\div\frac{c}{d}=\frac{x-1}{x}\div\frac{x}{1}=\frac{x-1}{x}*\frac{1}{x}=\frac{x-1}{x^2}$

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3 years ago