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Shkiper50 [21]
3 years ago
13

Missouri has a shape that is similar to a trapezoid with bases of about 198 miles and 276 miles and a height of about 270 miles.

What is the area of Missouri in square miles? Explain how you found the answer.

Mathematics
1 answer:
tiny-mole [99]3 years ago
8 0

Answer:

  63,990 mi²

Step-by-step explanation:

We can find the answer by using the formula for the area of a trapezoid and putting in the given numbers.

  A = (1/2)(b1 +b2)h . . . . where b1, b2 are the base lengths; h is the height

  A = (1/2)(198 mi +276 mi)(270 mi)

  A = 63,990 mi²

___

<em>Comment on the area of Missouri</em>

This estimate is about 8.2% low.

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You can only simplify the expression, because it doesn't equal anything. If you simplify it it would be:

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A triangular lot has sides of 215m, 185m, and 125m. Find the measures of the angles at its corners
Vlada [557]

Answer:

The measures of the angles at its corners are 59.1\°,35.4\°,85.5\°

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle A

Applying the law of cosines

185^{2}= 215^{2}+125^{2}-2(215)(125)cos(A)

2(215)(125)cos(A)= 215^{2}+125^{2}-185^{2}

cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))cos(A)=0.513953

A=arccos(0.513953)=59.1\°

step 2

Find the measure of angle B

Applying the law of cosines

125^{2}= 215^{2}+185^{2}-2(215)(185)cos(B)

2(215)(185)cos(B)= 215^{2}+185^{2}-125^{2}

cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))cos(B)=0.81489

B=arccos(0.81489)=35.4\°

step 3

Find the measure of angle C

Applying the law of cosines

215^{2}= 125^{2}+185^{2}-2(125)(185)cos(C)

2(125)(185)cos(C)= 125^{2}+185^{2}-215^{2}

cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))cos(C)=0.0784

C=arccos(0.0784)=85.5\°

3 0
3 years ago
The ratio of two numbers is 2/3. The sum of the numbers is 105. What are the two numbers?
Pepsi [2]
A) x/y = 2/3
B) x + y = 105
Solving Equation A for y
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Substituting A into B
B) x + 1.5x = 105
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x = 42
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8 0
3 years ago
Un edificio proyecta una sombra de 7.5m.mientras que un arbol que mide 1.6 m de altura proyecta una sombra 1.85 M¿Cual es la alt
sattari [20]

Answer: The height of the building is 6.49 meters.

Step-by-step explanation:

This can be translated to:

"A building projects a 7.5 m shadow, while a tree with a height of 1.6 m projects a shadow of 1.85 m.

Which is the height of the building?"

We can conclude that the ratio between the projected shadow is and the actual height is constant for both objects, this means that if H is the height of the building, we need to have:

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H/7.5m = 1.6m/1.85m

H = (1.6m/1.85m)*7.5m = 6.49m

The height of the building is 6.49 meters.

5 0
3 years ago
A music store sold a total of 27 used trumpets and clarinets in one month. Trumpets cost $149 and clarinets cost $99. If total s
vodomira [7]
Answer: 16

Solution:

1) Use letters to identify the variables:

Number of trumpets: t
Number of clarinets: c

2) Translate each statement into algebraic (mathematical) language.

2.1) Sold a total of 27 used trumpets and clarinets

=> t + c = 27

2.2) Trumpets cost $149 and clarinets cost $99

Total cost of the trumpets: 149t
Total cost of clarinets: 99c

Total cost = 149t + 99c

2.3) Total sales were $3223

=> 149t + 99c = 3223.

3) State the system of equations:

Equation (1) t + c = 27
Equation (2) 149t + 99c = 3223

4) Solve the system of equations:

4.1) Multiply equation 1 by 149:

=> 149t + 149c = 4023

4.2) Subtract the equation (2) from the equation obtained in 4.1

=> 149c - 99c = 4023 - 3223

=> 50c = 800

=> c = 800 / 50 = 16

5) Verify the solution:

From equation (1) t = 27 - 16 = 11

Total cost = 149*11 + 99*16 = 3223

Now you have a verified answer: they sold 16 clarinets
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