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cupoosta [38]
3 years ago
7

Solve 63 – x = 62 for x.

Mathematics
1 answer:
lara [203]3 years ago
4 0
63-x=62
Then subtract 62 and 63
-x=-1
x=1
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F) One number is 78 more than
vladimir2022 [97]

Answer:

The larger number = 116

Step-by-step explanation:

Let the smaller number = x

Given that one number is 78 more than  another, so

The larger number = x+78

Given that if we add 12 to the  smaller number, the result is 50, so

x+12=50

subtract 12 from both sides

x+12-12=50-12

Simplify

x=38

Therefore,

  • The smaller number = 38
  • The larger number = x+78 = 38+78 = 116

Thus, the larger number = 116

7 0
3 years ago
Integrate f(x,y,z)=20xz over the region in the first octant (x,y,z≥0) above the parabolic cylinder z=y2 and below the paraboloid
vodomira [7]
\displaystyle\iiint_Vf(x,y,z)\,\mathrm dV=20\int_{x=0}^{x=2}\int_{y=0}^{y=2}\int_{z=y^2}^{z=8-2x^2-y^2} xz\,\mathrm dz\,\mathrm dy\,\mathrm dx=\dfrac{1280}3
4 0
3 years ago
Read 2 more answers
A furniture store received an order for 3,456 chairs. they can fit 9 chairs in a large shipping box. how many shipping boxes wil
kykrilka [37]
This is simple :)
If 9 chairs can fit in one box, and you have 3,456 chairs, just divide how many chairs you have by how many can fit in the box in order to find how many boxes you will need.

3,456/9 = 384
384 boxes will be needed
7 0
4 years ago
Given f(x) = x²+x-6, find f(0).
levacccp [35]

Answer:

-6

Step-by-step explanation:

replace x with 0

3 0
2 years ago
The doubling period of a bacteria population is 10 minutes. At time t = 110 minutes, the bacterial population was 800.
goldenfox [79]

The initial population at time t = 0 was 0.39 while the size of the bacteria population after 4 hours was 6553600

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let y represent the bacteria population at time t. a represent the initial population at t = 0. Since the doubling period of a bacteria population is 10 minutes, hence:

y=a(2)^\frac{t}{10}

At time t = 110 minutes, the bacterial population was 800. Hence:

800=a(2)^\frac{110}{10} \\\\a = 0.39

At 4 hours (240 minutes):

y=0.39(2)^\frac{240}{10} =6553600

The initial population at time t = 0 was 0.39 while the size of the bacteria population after 4 hours was 6553600

Find out more on equation at: brainly.com/question/2972832

#SPJ1

4 0
2 years ago
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