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3 years ago

In order to be considered an ion, an atom must have a

2 answers:

7 0

In order to be considered an Ion, an Atom just has to have a Charge, so B.)Charge is the correct answer, and I just took the test and got it correct.

Igoryamba3 years ago

5 0

Answer is B, it can be positive or negative, as long as it has a charge.

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If an object has a net positive charge of 4.0 coulombs, the object possesses (1) 6.3 × 10^18 more electrons than protons (2) 2.5

Readme [11.4K]

Answer:

(4) $2.5 \times 10^{19}$ more protons than electrons

Explanation:

Total positive change on the object is given as

$Q = 4 C$

now by the law of quantization of charge we know that the charge on any body is always in form of integral multiple of charge of an electron.

So we will have

$Q = N e$

here we know that

$4 = N(1.6 \times 10^{-19})$

$N = 2.5 \times 10^{19}$

Now we know that the object is positively charged so here electrons must be less in numbers than protons

so correct answer will be

(4) $2.5 \times 10^{19}$ more protons than electrons

3 0

4 years ago

How many feet of wire does it take to make a slinky

xenn [34]

How many feet of wire does it take to make one Slinky? Each one is made from 80 feet of wire and over a quarter billion Slinkys have been sold worldwide.

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3 years ago

A smoke alarm beeps twice per minute. What is the period and frequency 1 po

oksian1 [2.3K]

Answer: the third one

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3 years ago

State the career function of electrical engineering

Flauer [41]

Answer:

Explanation:

Electrical engineers design, develop, and test electrical devices and equipment, including communications systems, power generators, motors and navigation systems, and electrical systems for automobiles and aircraft. They also oversee the manufacture of these devices, systems, and equipment.

7 0

3 years ago

Read 2 more answers

A solid cylindrical bar conducts heat at a rate of 25 W from a hot to a cold reservoir under steady state conditions. If both th

expeople1 [14]

Answer:

Using the new cylinder the heat rate between the reservoirs would be 50 W

Explanation:

Conduction could be described by the Law of Fourierin the form: $Q=kA\frac{T_1-T_2}{L}$ where $Q$ is the rate of heat transferred by conduction, $k$ is the thermal conductivity of the material, $T_1$ and $T_2$ are the temperatures of each heat deposit, $A$ is the cross area to the flow of heat, and ${L}$ is the distance that the flow of heat has to go.
For the original cylinder the Fourier's law would be: $kA_1\frac{T_1-T_2}{L_1}=25W$ , and if $A_1=\frac{\pi D_{1}^{2}}{4}$ , then the expression would be: $k\frac{\pi D_1^{2}}{4} \frac{T_1-T_2}{L_1}=25W$ where $D_1$ is the diameter of the original cylinder, and ${L_1}$ is the length of the original cylinder.
For the new cylinder, in the same fashion that for the first, Fourier's Law would be: $Q_2=k\frac{\pi D_2^2}{4}\frac{T_1-T_2}{L_2}$ ,where $Q_2$ is the heat rate in the second case, $D_2$ and ${L_2$ are the new diameter and length.
But, $D_2=2D_1$ and $L_2=2L_1$ , substituting in the expression for $Q_2$ : $Q_2=k\frac{\pi (2D_1)^2}{4}\frac{T_1-T_2}{2L_1}$ .
Rearranging: $Q_2=\frac{2^2}{2}(k\frac{\pi D_1^2}{4}\frac{T_1-T_2}{L_1})$ .
In the last declaration of $Q_2$ , it could be noted that the expressión inside the parenthesis is actually $Q_1$ , then: $Q_2=\frac{2^2}{2}(25W)=50W$ .
<u>It should be noted, that the temperatures in the hot and cold reservoirs never change.</u>

7 0

4 years ago