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JulijaS [17]
3 years ago
9

GIVING BRAINLIEST PLEASE HELP!!

Physics
1 answer:
Degger [83]3 years ago
8 0
D. and it’s not 23 points it’s 12
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Look at the diagram showing the different wavelengths in sunlight.
Alex777 [14]

Answer:

Explanation:

They are infrared waves which mean they take the form of heat.

6 0
3 years ago
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The wave speed on a string under tension is 200 m/s. What is the speed if the tension is doubled?
Maksim231197 [3]

Answer:

v = 282.84 m / s

Explanation:

The speed of a wave in a wire is given by the equation

       .v = √ T /ρ

Where v is the speed of the wave, T the tension in the wire and ρ the density of the wire

 If the tension is doubled

        T = 2T₀

        v = √ (2T₀ / ρ)

        v = √2   √ T₀ / ρ

        v = √2  v₀

calculate

       v = √2  200

       v = 282.84 m / s

3 0
3 years ago
Please I need an answer
eduard
B or c
It’s kinda confusing
7 0
3 years ago
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A 10- kg ball starting from rest rolls down a 5 m tall smooth hill from one person to another person who is standing at the bott
olya-2409 [2.1K]

Answer: 3.13 m

Explanation:

Given

mas of the ball is m=10 kg

The ball rolls down a vertical distance of 5 m

Spring constant of spring is k=100\ N/m

Here, the potential energy of the ball converted into kinetic energy which in turn converts into elastic potential energy

\Rightarrow mgh=\frac{1}{2}kx^2\quad [\text{x=compression in the spring}]\\\\\Rightarrow 10\times 9.8\times 5=\frac{1}{2}\cdot 100\cdot x^2\\\Rightarrow x=\sqrt{9.8}\\\Rightarrow x=3.13\ m

Thus, the spring compresses by 3.13 m.

6 0
3 years ago
An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard that is at a distance o
Minchanka [31]

Answer:

B. 0.16 m

Explanation:

The vertical distance by which the player will miss the target is equal to the vertical distance covered by the dart during its motion.

Since the dart is thrown horizontally, the initial vertical velocity is zero:

v_y = 0

While the horizontal velocity is

v_x = 15 m/s

The horizontal distance covered is

d_x = 2.7 m

Since the dart moves by uniform motion along the horizontal direction, the time it takes for covering this distance is

t=\frac{d_x}{v_x}=\frac{2.7 m}{15 m/s}=0.18 s

along the vertical direction, the motion is a uniformly accelerated motion with constant downward acceleration g=9.8 m/s^2, so the vertical distance covered is given by

d_y = \frac{1}{2}gt^2=\frac{1}{2}(9.8 m/s^)(0.18 s)^2=0.16 m

8 0
4 years ago
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