The electric force between two objects with charge q1 and q2 is given by
![F=k_e \frac{q_1 q_2}{d^2}](https://tex.z-dn.net/?f=F%3Dk_e%20%20%5Cfrac%7Bq_1%20q_2%7D%7Bd%5E2%7D%20)
where ke is the Coulomb's constant while d is the distance between the two charges.
We can see that the force F scales as the inverse of the square of the distance:
![\frac{1}{d^2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bd%5E2%7D%20)
. Therefore, when the two objects move apart from each other, the distance increases and therefore the force between them decreases.
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Answer:
The electric field produced by this disk along the x axis at point (P = 1.01 m, 0.00 m) is 996.54 N/C
Explanation:
The electric field produced by this disk along the x axis at point (P = 1.01 m, 0.00 m), will be evaluated as follows:
Since x > 0
σ is surface charge density = 5.88 × 10⁻⁶ C / m²
R is the radius = 7.52cm = 0.0752m
position x = 1.01m
k is coulomb force constant = 8.99 × 10⁹ Nm² / C²
= 996.54 N/C
Therefore, The electric field produced by this disk along the x axis at point (P = 1.01 m, 0.00 m) is 996.54 N/C