Average speed = (distance covered) / (time to cover the distance).
Distance covered = 437 km = 437,000 meters
Time to cover the distance = (7.27 hrs) x (3600 sec/hr) = 26,172 seconds
Average speed = (437,000 meters) / (26,172 seconds)
Average speed = 16.7 m/s
The hawk’s centripetal acceleration is 2.23 m/s²
The magnitude of the acceleration under new conditions is 2.316 m/s²
radius of the horizontal arc = 10.3 m
the initial constant speed = 4.8 m/s
we know that the centripetal acceleration is given by
= 
= 23.04/10.3
= 2.23 m/s²
It continues to fly but now with some tangential acceleration
= 0.63 m/s²
therefore the net value of acceleration is given by the resultant of the centripetal acceleration and the tangential acceleration
so
= 
= 
= 2.316 m/s²
So the magnitude of net acceleration will become 2.316 m/s².
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Answer:
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Explanation: