Answer:
sorry in a hurry
Step-by-step explanation:
A rocket gets launched straight up into space. What is a possible description
of the rate of change (slope)?
456- 12= 444
37×12= 444
=12
Answer:
By AA
ΔWXY ~ΔWVZ
Step-by-step explanation:
Here WXY is an isosceles triangle with legs WX & WY
So WX = WY
Hence ∠X = ∠Y
So ∠2= ∠3.
Now by angle sum property
∠1 + ∠2+∠3 = 180°
∠1+∠2+∠2=180°
2∠2 = 180° - ∠1 .......(1)
In triangle WVZ
WV = WZ
So ∠V = ∠Z
∠4 = ∠5
Once again by angle sum property
∠1 + ∠4 + ∠5=180°
∠1 + ∠4 + ∠4 = 180°
2∠4 = 180° - ∠1 ...(2)
From (1) & (2)
2∠2 = 2∠4
∠2=∠4
Now ∠W is common to both triangles
Hence by AA
ΔWXY ~ΔWVZ
Answer:
Question one: Zero slope
Question two: 
Step-by-step explanation:
Given the following questions:
<u>Question one:
</u>The following line is what you call a "zero slope." Zero slopes are lines that are neither decreasing or increasing and remain at a constant or just a straight line.
Question two:
Point A = (-2, -3) = (x1, y1)
Point B = (2, -3) = (x2, y2)
Using the formula for slope or rise over run we will solve and find the slope of this line.



The slope of this line is "0/4."
Hope this helps.
Answers
remove the ( ) fast and then add the numbers that look the same.
(22+19b)+7
22+19b+7
22+7+19b
= 29+19b
18+(5+6m)
18+5+6m
= 23+6m
here u don't care about same or not same u just multiply or divide
11s(4)
= 44s
10y(7)
= 70y
(9+31+5)(7times5)times4)
(45)(35)4
(1575)4
= 6300