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olya-2409 [2.1K]

4 years ago

8

Heather eats a jelly sandwich every 5th day and drinks milk every 4th day. If she had a jelly sandwich and milk today, how many

days will pass before she will have both again?

1 answer:

Nadusha1986 [10]4 years ago

6 0

20 days, becuase 5*4= 20

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Bonnie has been hired to make a frame to go around a large mural. She will have 300 tiles to use. How many tiles should she plac

sp2606 [1]

Answer:

she should place 76 tiles along 1 side of the square

Step-by-step explanation:

300 = 4n - 4

answer will leave u with n=76

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3 years ago

Inverse of y=x^2-10x

Fittoniya [83]

The answer is f(x)‐¹=(+/-)x+25+5

7 0

3 years ago

A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte

ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, $q_1 = Q- r \times Q$

$q_1 = Q(1-r)\cdots(i)$

The value of quantity after 2 months, $q_2 = q_1- r \times q_1$

$q_2 = q_1(1-r)$

From equation (i)

$q_2=Q(1-r)(1-r) \\\\q_2=Q(1-r)^2\cdots(ii)$

The value of quantity after 3 months, $q_3 = q_2- r \times q_2$

$q_3 = q_2(1-r)$

From equation (ii)

$q_3=Q(1-r)^2(1-r)$

$q_3=Q(1-r)^3$

Similarly, the value of quantity after n months,

$q_n= Q(1- r)^n$

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

$q_{48}=Q(1-r)^{48}$

Putting Q=6200 and r=5.5%=0.055, we have

$q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32$

Hence, the value of quantity after 4 years is 410.32.

4 0

3 years ago

Read 2 more answers

The graph of which function passes through (0,3) and has an amplitude of 3? f (x) = sine (x) + 3 f (x) = cosine (x) + 3 f (x) =

Cloud [144]

Answer:

$f(x)=3*cosine(x)$

Step-by-step explanation:

We are looking for a trigonometric function which contains the point (0, 3), and has an amplitude of 3.

We know that for a sine function $f(x)=sin(x)$ , $f(0)= 0$ ; therefore the function we a looking for cannot be a sine function because it is zero at $x=0$ .

However, the cosine function $f(x)=cos(x)$ gives non-zero value at $x=0:$

$f(0)=cos(0)=1$

therefore, a cosine function can be our function.

Now, cosine function with amplitude $a$ has the form

$f(x)=a*cos(x)$

this is because the cosine function is maximum at $x= 0$ and therefore, has the property that

$f(0)=a*cos(0)= a$

in other words it contains the point $(0, a)$ .

The function we are looking for contains the point $(0, 3)$ ; therefore, its amplitude must be 3, or

$f(x)=3cos(x)$

we see that this function satisfies our conditions: $f(x)$ has amplitude of 3, and it passes through the point (0, 3) because $f(0)=3$

8 0

4 years ago

Read 2 more answers

Pete adds 78 to the fata set below. 20,32,32,45,50. Which statement below will be true?

ozzi

Answer:

the inter-quartile range will increase

Step-by-step explanation:

The initial data-set was;

20,32,32,45,50

Adding a new value 78 will have several effects;

The mean of the new set of values will increase since 78 is mostly likely to be an outlier.

The median of the new data set will increase. The median of the old data set is 32 while that of the new data set will be 38.5

The mode is the most frequent observation. Both the new and the old sets of values will have a mode of 32. The mode will therefore remain the same.

The inter-quartile range just like the range will increase

4 0

3 years ago