Question

P+n=131p+3.26n=248.52

Answer 1

Answer

Solution:

p = 79

n = 52

Step-by-step explanation:

Given equations:

A) $p+n=131$

B) $p+3.26n=248.52$

To solve for  $p$ and $n$

Naming the first equation as A and second as B.

Using elimination method to solve.

In order to eliminate $p$ we subtract equation A from B.

Subtracting A from B i.e [$B-A$

  (B) $p+3.26n=248.52$  

- (A)  $p+n=131$

We get,  $3.26n-n=248.52-131$

$2.26n=117.52$

Dividing both sides 2.26.

$\frac{2.26n}{2.26}=\frac{117.52}{2.26}$

∴ $n=52$

We can solve for $p$ by substituting $n=52$ in equation A.

$p+52=131$

Subtracting both sides by 52.

$p+52-52=131-52$

∴ $p=79$