All categories

3 years ago

Mrs. Robertson is taking a picture of three students-Zach, John, and

Mathematics

1 answer:

DanielleElmas [232]3 years ago

3 0

I would say 6 . \/ /\ | __ ⇘ ⇙ ( Those are the directions I was going for)

I hope this helped !

You might be interested in

In the name carbon dioxide, the prefix of the second word indicates that a molecule of carbon dioxide contains

kherson [118]

Answer:

The correct option is B. two oxygen atoms

Step-by-step explanation:

The molecular formula for carbon dioxide is given by :

$CO_2$

Here, the alphabet C stands for Carbon and the alphabet O stands for Oxygen.

And the prefixes of each of these words represents the number of atoms present of the corresponding element in one molecule of carbon dioxide.

So, The prefix of the first word that is C is 1

⇒ One molecule of carbon dioxide contains one atom of Carbon.

The prefix of the second word that is O is 2

⇒ One molecule of carbon dioxide contains 2 atoms of Oxygen.

Therefore, The correct option is B. two oxygen atoms

7 0

3 years ago

Read 2 more answers

HELP ME RQ PLEASEEEEEEEEEEEEEEEEE

sveticcg [70]

Answer:

It is D

Step-by-step explanation:

60 is a solid number which is crucial in the first step of solving a problem.

Hope this helped!

8 0

3 years ago

At the Demarest Mountain ski slope lounge, they serve hot cocoa. A serving of

Bad White [126]

Answer: 30 more servings

Explanation:
They had 90 tablespoons, but half are gone. 90/2 = 45

Each serving is 1.5 tablespoons.

45/1.5 = 30 more servings

4 0

2 years ago

Read 2 more answers

The probability of an archer hitting her target is 83%. Suppose she has 20 shots to take, and each shot is independent of the ot

Bad White [126]

The answer/ the mean is 16.6

8 0

3 years ago

Two coworkers commute from the same building. They are interested in whether or not there is any variation in the time it takes

jenyasd209 [6]

Answer:

Step-by-step explanation:

Hello!

You have two samples.

Sample 1 (time that takes one commute of worker 1)

n₁= 20

S₁²= 12.2

Sample 2 (time that takes one commute of worker 2)

n₂= 20

S₂²= 16.9

The hypothesis is that the first coworker is more consistent with his commute times, this means that the variability of his commute times is less than the variability of the commute times of worker 2. With this in mind, the hypothesis for a variance ratio test is:

H₀: σ₁² ≥ σ₂²

H₁:: σ₁² < σ₂²

α: 0.10

The statistic for this test is:

F= (S₁²/S₂²) * (σ₁²/σ₂²) ~ F $_{n1-1;n2-1}$

The test is one-tailed (left) with just one critical value:

$F_{n_1-1;n_2-1;\alpha } = \frac{1}{F_{n_2-1;n_1-1;1-\alpha }} = \frac{1}{F_{19;19;0.90}} = \frac{1}{1.82} =0.549$

(The F-table I use only has the values for high probabilities so I've used a conversion method to obtain the value for the small probability)

Your decision rule is:

If F ≤ 0.549, you reject the null hypothesis.

if F > 0.549, you support the null hypothesis.

The calculated value:

F= (S₁²/S₂²) * (σ₁²/σ₂²) = (12.2/16.9) * 1= 0.722

Since the calculated F-value is greater than the critical value, the decision is to not reject the null hypothesis. So you can say that the variability of the commute times of worker 1 is less than the variability of the commute times of worker 2.

I hope you have a SUPER day!

7 0

3 years ago