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3 years ago

NEED HELP! Which equation represents a circle with a center at (-5,5) and a radius of 3 units?

Mathematics

2 answers:

Alja [10]3 years ago

7 0

Equation of the circle is (x + 5)² + (y - 5)² = 9

Step-by-step explanation:

Step 1: Given center is (h, k) = (-5, 5) and radius is 3. Equation of a circle is given by (x - h)² + (y - k)² = r²

Equation is (x - -5)² + (y - 5)² = 3²

⇒ (x + 5)² + (y - 5)² = 9

creativ13 [48]3 years ago

6 0

Answer:

(x + 5)² + (y - 5)² = 9

Step-by-step explanation:

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What is the slope of (-2,7); (-5,3)

Vinvika [58]

Answer:

1 1/3

Step-by-step explanation:

m = y2-y1 over x2-x1

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3 years ago

Does the graph at the right represent a linear function? Explain.

kondaur [170]

Answer:

see below

Step-by-step explanation:

This is not a linear function because it does not pass the vertical line test

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8 0

3 years ago

PLEASE HELP PLEASEEEEE

gulaghasi [49]

Answer:

Answer:

5.46π cm³

Step-by-step explanation:

Volume of sphere= 4/3πr³

= 4/3×π×(1.6)³ cm³

=5.46π cm³

hope this helped you!

4 0

3 years ago

Turning off the water while brushing your Teeth saves 350 centilliters of water. How many liters of water can you save if you tu

Blababa [14]

Answer:

1.1l

Step-by-step explanation:

350×3=1050cl

=1.05l

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3 0

3 years ago

I need help! Will mark Brainliest for full answer!!!

Softa [21]

Answer:

Part a .............> x = 11

Part b .............> k = 57.2

Part c .............> y = 9.2

Explanation:

The three problems deal with inverse variation between two variables

An inverse variation relation between two variables means that when one of the variables increases, the other will decrease (and vice versa)

Mathematically, an inverse variation relation is represented as follows:

$y = \frac{k}{x}$

where x and y are the two variables and k is the constant of variation

Now, let's check the givens:

Part a:

We are given that y = 3 and k = 33

Substitute in the original relation and solve for x as follows:

$y = \frac{k}{x}\\ \\3 = \frac{33}{x}\\ \\x=\frac{33}{3}=11$

Part b:

We are given that y = 11 and x = 5.2

Substitute in the original relation and solve for k as follows:

$y=\frac{k}{x}\\ \\11=\frac{k}{5.2}\\ \\k=11*5.2=57.2$

Part c:

We are given that x=7.8 and k=72

Substitute in the original relation and solve for y as follows:

$y=\frac{k}{x}=\frac{72}{7.8}=9.2$ to the nearest tenth

Hope this helps :)

6 0

3 years ago