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2 years ago

for simultaneous equations in variables x and y d x² = 49 Dy= -63, D= 7 then what is the value of x?

Mathematics

1 answer:

Ket [755]2 years ago

3 0

Step-by-step explanation:

hope it will be helpful to you

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The amount of the radioactive substance is 374.6 g

<h3>How to determine the amount of radioactive substance?</h3>

The given parameters are:

Initial, a = 424 mg
Rate, r = 6%
Time, t = 2 hours

The amount of the radioactive substance is calculated as:

A(t) = a(1 - r)^t

This gives

A(t) = 424 * (1 - 6%)^t

At 2 hours, we have:

A(2) = 424 * (1 - 6%)^2

Evaluate

A(2) = 374.6

Hence, the amount of the radioactive substance is 374.6 g

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REY [17]

Answer:

Midpoint is $(\frac{-37 }{2}, 14)$

Step-by-step explanation:

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2})$

= $(\frac{-11 -26}{2}, \frac{30 - 2 }{2})$

= $(\frac{-37 }{2}, \frac{28 }{2})$

= $(\frac{-37 }{2}, 14)$

Midpoint is (-37/2, 14)

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3 years ago

for simultaneous equations in variables x and y d x² = 49 Dy= -63, D= 7 then what is the value of x?​

for simultaneous equations in variables x and y d x² = 49 Dy= -63, D= 7 then what is the value of x?