The oxidation of sulfur in H2SO4 is +6.
Answer:
By conducting a chemical reaction.
Explanation:
To form a new substance from old ones, you have to allow the old substances to react with each other, forming something different.
Answer:
The transition-metal have the highest oxidation number is Mo in Rb₃[MoO₃F₃]
Explanation:
Transition metals are metals that are found in the middle of the periodic table.
For the compounds:
Rb₃[MoO₃F₃]: Rb is an alkali metal that has a charge of +1. that means [MoO₃F₃] is -3. The oxyfluoride O₃F₃ has a charge of -9. That means the <em>Mo is +6</em>
K₄[Mn(CN)₆]: Potassium is +1, thus, the [Mn(CN)₆] is -4, As the CN is -1 and there are 6, the <em>Mn is +2</em>
Na[Ag(CN)₂]: As Na is +1, the [Ag(CN)₂] is -1. As CN are -1, the <em>Ag is +1</em>
K₂[PtCl₆]: Potassium is +1, the [PtCl₆] is -2, As the Cl are -1, the <em>Pt is +4</em>
[Co(NH₃)₄Cl₂]: The NH₃ are neutral, The Cl are -1, that means the <em>Co is +2.</em>
The transition-metal have the highest oxidation number is<em> Mo +6</em>
I hope it helps!
Molarity : It is defined as the number of moles of solute present in one liter of solution.
Therefore, the molarity of solution is 3.33
I would use the following steps:
- Write the <em>balanced chemical equation</em> for the reaction.
- Use the molar mass to <em>convert the mass of the reactant to moles</em>.
- Use the molar ratio of product:reactant from the balanced chemical equation to <em>convert moles of reactant to moles of product</em>.
- Use the molar mass of the product to <em>convert moles of product to mass of product</em>.
You can use the diagram below to remind you of the importance of the <em>molar ratio</em> in mass-mass conversions
You must get over the mole “hill” to make the conversion.