I don't know what your asking so Identify means your self
To decrease the rate of the forward reaction you can do the following:
- decrease the concentration of the reactants
- increase the concentration of the products
- increase the pressure so the hydrogen gas will not be easily removed from the reaction
- decrease the temperature, number of collisions will decrease so the rate of the reaction will decrease
Answer:
Hydrogen bonding, Dipole-dipole
Explanation:
Let us look closely at the structure of H2S, this will enable us to decide if it will show dipole-dipole interaction or not. Given that Sulphur has a greater electro negativity compared to Hydrogen, we expect that the S – H bond will be a polar bond with the direction of polarity pointing towards the sulphur atom according to the usual convention in chemistry. Now, we know that H2S is a bent molecule (there are two lone pairs on the central sulphur atom which leads to a bent molecular geometry), therefore, the vectorial sum of the bond dipole moments will produce a non- zero total dipole moment. This implies that there is a permanent non-zero dipole moment in H2S therefore we expect the molecule to exhibit dipole-dipole interactions .
Similarly, we know that hydrogen bonding exists when hydrogen is bonded to a highly electronegative element such as fluorine, sulphur, oxygen etc. In H2S, hydrogen is bonded to sulphur hence we expect that there should be hydrogen bonding between H2S molecules. Hydrogen bonding is actually a type of dipole-dipole interaction.
a
The speed of molcules in gas mood are more than liquide
