Answer:
0.0252mol/L
Explanation:
The following data were obtained obtained from the question:
Volume of solution = 284mL = 284/1000 = 0.284L
Mole of CuSO4 = 7.157 × 10^-3 mol
Molarity =?
Molarity = mole/Volume
Molarity = 7.157x10^-3 /0.284
Molarity = 0.0252mol/L
The concentration of the solution is 0.0252mol/L
Answer:
B. 0.92 M
Explanation:
Molarity of a solution = number of moles (n) ÷ volume (V)
According to the information provided in this question;
mass of NaCl = 42g
Volume of water = 780mL
Using mole = mass/molar mass
Molar mass of NaCl = 23 + 35.5 = 58.5g/mol
mole = 42/58.5
mole (n) = 0.72mol
Volume (V) = 780 mL = 780/1000 = 0.780 L
Hence, molarity = n/V
Molarity = 0.72/0.780
Molarity = 0.923 M
Firstly calculate the grams in the last 8 percent before moving onto the pyrite section.
50.8x0.08=4.064g
We know that iron ore in this case has 92 percent pyrite which contains 46.5 percent iron so we do 50.8x0.92=46.736g from this we need to find 46.5 percent of the iron content in the 92 percent pyrite section then add this answer to the 8 percent of iron ore we found at the start.46.736x0.465=21.73224g
21.73224g+4.064=25.79624g of iron ore 25.8g(3sf)
the numbers are going to be small so like a power but its at the bottom
NH3, H2O2, NHO2
