Answer:
The mass of water produced is 4.29 g.
Explanation:
Given;
reacting mass of ethane, C₂H₆ = 2.5 g
reacting mass of oxygen, O₂ = 5.0 g
The balanced combustion reaction is given as follows;
2C₂H₆ + 7O₂ ----------------> 4CO₂ + 6H₂O
Based on the balanced equation above;
requires
7.0 moles of oxygen -----------------------> 2.0 moles of ethane
requires
5.0 g of oxygen --------------------------> x gram of ethane
x = (2 x 5) / 7
x = 1.43 g
Ethane is in excess of 1.07g (2.5 g - 1.43g)
Now, determine the mass of water produced by 1.43 g of ethane;
requires
2.0 moles of ethane -----------------------> 6.0 moles of water
requires
1.43 g of ethane --------------------------> y gram of water
y = (6 x 1.43) / 2
y = 4.29 g
Therefore, the mass of water produced is 4.29 g.
Add up all the grams to get 9.96, then divide the amount if each element by the total;
4.56 of Pb divided by 9.96 = 0.4578313 now multiply by 100 and get 45.8% of Pb, then do the same for the rest of the elements, hope this helped <3
Answer:because you are lifting the box higher
Explanation:it has a higher gravitational pull
Answer:
Explanation:
Hello,
In this case, we work on a dilution process in which we can state that the moles remain the same after the dilution process. In such a way, we can write:
That in terms of molarities and volumes is:
Whereas is the initial molarity (3.00 M) of the stock solution, the molarity of the diluted solution (0.289 M), the aliquot of the stock (concentrated) solution and the volume of the diluted solution (100 mL), thus, we compute as required:
Best regards.