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aleksley [76]
3 years ago
13

explain in your own words how you would determine the mass of a product in a chemical reaction (theoretical yield) if you know t

he mass of reactant.

Chemistry
1 answer:
ANTONII [103]3 years ago
8 0

I would use the following steps:

  1. Write the <em>balanced chemical equation</em> for the reaction.
  2. Use the molar mass to <em>convert the mass of the reactant to moles</em>.
  3. Use the molar ratio of product:reactant from the balanced chemical equation to <em>convert moles of reactant to moles of product</em>.
  4. Use the molar mass of the product to <em>convert moles of product to mass of product</em>.

You can use the diagram below to remind you of the importance of the <em>molar ratio</em> in mass-mass conversions

You must get over the mole “hill” to make the conversion.


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Kaylis [27]

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Warm blood gives deep-sea fish a boost, according to Wegner. The opah's muscles and nervous system likely function faster than an equivalent fish with cold blood. ... This fish, the southern opah, lives in colder waters than the northern opah, so it would be harder to keep warm, Wegner said — but even more beneficial.

4 0
3 years ago
In the reaction N2O4(g) 2NO2(g), what changes in color would you expect as pressure is increased at constant temperature?
skelet666 [1.2K]

Answer:

Brown color of the solution decreases

Explanation:

NO_2 is brown in color whereas N_2O_4 is colorless.

Equilibrium reaction between NO_2 and N_2O_4 is as follows:

2NO_2\leftrightharpoons N_2O_4

As per the Le Chatelier's principle, if pressure of a equilibrium is increased, the equilibrium will shift in the direction having fewer no. of moles of gases.

In the given equilibrium, NO_2 side has more no. of moles. So on increasing pressure, equilibrium will shift towards the side of N_2O_4 or more formation of N_2O_4 will take place.

Therefore, more NO_2 will decompose that will decrease the brown color of the solution as N_2O_4 is colorless.

6 0
3 years ago
A 100g sample of a metal was heated to 100oC and then quickly transferred to an insulated container holding 100g of water at 22o
Lady_Fox [76]

Answer:

B) The metal temperature changed more than the water temperature did, but the metal lost

the same amount of thermal energy as the water gained.

Explanation:

Heat capacity or thermal capacity is defined as the amount of heat required by a given mass of a material to raise its temperature by one unit which means that the heat capacity of the water, that is the quantity of heat required to cause a rise from 22°C to 35°C that is a rise of 13°C is the quantity of heat that caused the drop in temperature of the metal from 100°C to 35°C a change of 65°C

The water has more capacity to absorb heat or a higher heat capacity than the metal

However, the first law of thermodynamics states that energy is neither created nor destroyed, but it changes from one form to another. In this case, the thermal energy lost by the metal is the same as the thermal or heat energy gained by the water

4 0
3 years ago
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring
Lady_Fox [76]

Answer:

The standard cell potential is 1.40 V. The correct option is the option  D (+1.40 V)

Explanation:

Oxide-reduction reactions, also called redox, involve the transfer or transfer of electrons between two or more chemical species. In these reactions two substances interact: the reducing agent and the oxidizing agent.

An oxidizing element or oxidizing agent is one that reaches a stable energy state as a result of which the oxidant is reduced and gains electrons. The oxidizing agent causes oxidation of the reducing agent generating the loss of electrons of the substance and, therefore, oxidizes in the process.

In other words, the oxidizing agent is that chemical species that in a redox process accepts electrons released by the reducing agent and, therefore, is reduced in said process. The oxidizing agent is reduced because, upon receiving electrons from the reducing agent, a decrease in the value of the charge or oxidation number of one of the atoms of the oxidizing agent is induced .

Electrochemical cells, galvanic cells or batteries are called devices that are capable of transforming chemical energy originated in a spontaneous redox process into electrical energy.

The cellular potential is generally in standard conditions, that is, 1 M with respect to solute concentrations in solution and 1 atm for gases.

In this case you have the reaction:

3 Cl₂(g) + 2 Fe(s) → 6 Cl⁻(aq) + 2 Fe³⁺(aq)

In this case the following half-reactions occur:

Semi-reaction of oxidation ( an atom or group of atoms loses electrons, or increases its positive charges): Fe³⁺(aq) + 3 e- -->Fe(s); E⁰ = -0.04 V

Semi-reaction of reduction (an atom or group of atoms gains electrons, increasing its negative charges): Cl₂(g) + 2 e- --> 2 Cl-(aq); E⁰=1.36 V

In an electrochemical cell at 25°C  the potentials of the  semi-reactions are usually measured  in the sense of reduction  and generally the standard potential between both electrochemical cells will be:

E^{0} =E^{0} _{reduction} -E^{0} _{oxidation}

E⁰=1.36 V - (-0.04 V)

E⁰=1.36 V + 0.04 V

<em>E⁰=1.40 V</em>

<em><u>The standard cell potential is 1.40 V. The correct option is the option  D (+1.40 V)</u></em>

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