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3 years ago

(GIVING BRAINLIEST!!)

Mathematics

2 answers:

Mashcka [7]3 years ago

5 0

Answer:

Step-by-step explanation:

The answer is d

Elanso [62]3 years ago

3 0

Answer:

Step-by-step explanation:

I did the test and got it right.

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(x-2)= - 1/4(x-8) what does x equal?

Alona [7]

Answer:

16/5 or 3 1/5 i think

Step-by-step explanation:

8 0

3 years ago

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Which pair of triangles is congruent?

daser333 [38]

You are only showing one pair of triangles

4 0

3 years ago

shape ABCDEF is an irregular hexagon. prove that the sum of the shape is720 degrees. show ur working. (3marks)

guajiro [1.7K]

Answer:

Here's one way to do it

Step-by-step explanation:

Divide the hexagon into triangles, for example, as in the diagram below.

The triangles are all inside the hexagon, so the sum of their interior angles is the sum of those of the hexagon.

The sum of the interior angles of a triangle is 180°.

There are four triangles, so

Sum of interior angles = 4 × 180° = 720°

8 0

3 years ago

Write the integral that gives the length of the curve y = f (x) = ∫0 to 4.5x sin t dt on the interval [0,π].

Troyanec [42]

Answer:

Arc length $=\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx$

Arc length $=9.75053$

Step-by-step explanation:

The arc length of the curve is given by $\int_a^b \sqrt{1+[f'(x)]^2}\ dx$

Here, $f(x)=\int_0^{4.5x}sin(t) \ dt$ interval $[0, \pi]$

Now, $f'(x)=\frac{\mathrm{d} }{\mathrm{d} x} \int_0^{4.5x}sin(t) \ dt$

$f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( [-cos(t)]_0^{4.5x} \right )$

$f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( -cos(4.5x)+1 \right )$

$f'(x)=4.5sin(4.5x)$

Now, the arc length is $\int_0^{\pi} \sqrt{1+[f'(x)]^2}\ dx$

$\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx$

After solving, Arc length $=9.75053$

5 0

3 years ago

Simplify the expression where possible.(-4 x^2 )^2

Oduvanchick [21]

Answer:

$16x^{4}$

Step-by-step explanation:

$(a^{m})^{n}=a^{m*n} \\\\\\$ and $(a*b)^{m}= a^{m}*b^{m}$

$(-4x^{2})^{2} = (-4)^{2} *(x^{2})^{2}\\\\\\=16 * x^{2*2}\\\\=16x^{4}$

6 0

3 years ago