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3 years ago

Solve 2x^+8=0 by graphing the related function

Mathematics

2 answers:

garri49 [273]3 years ago

7 0

Answer:

No real solution.

Step-by-step explanation:

Please find the attachment.

We have been given a function $2x^2+8=0$ . We are asked to find the solution for our given function by graphing method.

We can see that our given function is an upward parabola. We know that solution of parabola is points, where graph intersects x-axis.

We can see from our attachment that our given function never intersects x-axis, therefore, there is no real solution for our given function.

posledela3 years ago

5 0

You cannot solve this equation by graphing because there are no real solutions.

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4 years ago

If 2+12=18, find the value of 3−13.

mojhsa [17]

Answer:

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Step-by-step explanation:

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3 years ago

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2 (Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!

Ivanshal [37]

Answer:

This series is divergent

Step-by-step explanation:

we are given a series

Firstly, we will find nth term

Numerator:

3, 4, 5,...

so, nth term will be

$a_n=n+3$

Denominator:

4,5,6,....

so, nth term will be

$b_n=n+4$

so, we can find it's nth term as

$c_n=\frac{n+3}{n+4}$

we can use divergent test

$\lim_{n \to \infty} c_n=\lim_{n \to \infty} \frac{n+3}{n+4}$

we can divide top and bottom by n

$\lim_{n \to \infty} c_n= \lim_{n \to \infty} \frac{n/n+3/n}{n/n+4/n}$

$\lim_{n \to \infty} c_n= \lim_{n \to \infty} \frac{1+3/n}{1+4/n}$

now, we can plug n=inf

$\lim_{n \to \infty} c_n= \frac{1+0}{1+0}$

$\lim_{n \to \infty} c_n=1$

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3 years ago

Find the value of x

luda_lava [24]

You need to post an equation if you want an answer, because without the equation it is impossible to determine the value of the coefficient x

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3 years ago

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Andreyy89

Answer:

I am sorry. To answer a test is against the Honor Code, I cannot help you.

Step-by-step explanation:

Remember PEMDAS :)

3 0

3 years ago

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