Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.
Answer:
44fps, or 44:1
Step-by-step explanation:
it is already a unit rate
Y=6x-5
f(x)=5x-6
can be function of equation but since it is asking for function the 2nd one is best
Answer:
Could you post the instructions
Step-by-step explanation:
Answer:
x>4
Step-by-step explanation:
Use the distributive property to multiply 2 by x−3.
2x−6+5x<9x−14
Combine 2x and 5x to get 7x.
7x−6<9x−14
Subtract 9x from both sides.
7x−6−9x<−14
Combine 7x and −9x to get −2x.
−2x−6<−14
Add 6 to both sides.
−2x<−14+6
Add −14 and 6 to get −8.
−2x<−8
Divide both sides by −2. Since −2 is <0, the inequality direction is changed.
x>-8/-2
Divide −8 by −2 to get 4.
x>4
Please give me the Brainliest answer!!!!