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Andre45 [30]
3 years ago
13

Which ratios form a proportion.? A)3/15,12/55 B)8/24,12/35 C)5/18,25/90 D)4/11,16/25

Mathematics
2 answers:
mote1985 [20]3 years ago
6 0
C is the answer (5/18,25/90)
Yuliya22 [10]3 years ago
4 0
Answer is C!

Ok I got to organize the info...
3/15 and 12/55
3*2...
Aha
3*4 equals 12 but not 15...
A: No

B:
8/24 12/35
No

GAUTIE
Sorry...
It's C
5/18 = 25/90
5*5=25
18*5 = 90
Hope that helps you!
One more happy customer!
 <3



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X+x²=30
x²+x-30=0
(x+6)(x-5)=0
x=-6 or x=5
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What are the values of the trigonometric ratios for this triangle?
Norma-Jean [14]
We know that
in the right triangle

<span>sinθ=opposite side/hypotenuse
</span><span>cosθ=adjacent side/hypotenuse
</span><span>tanθ=opposite side/adjacent side

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opposite side angle </span>θ=8
adjacent side angle <span>θ=15
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so

</span>sinθ=8/17
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4 0
3 years ago
The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3
In-s [12.5K]

Answer:

a) There is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) There is a 1-0.0548 = 0.9452 = 94.52% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

c) There is a 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3 minutes. This means that \mu = 8.3, \sigma = 3.3.

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

We are working with a sample mean of 37 jets. So we have that:

s = \frac{3.3}{\sqrt{37}} = 0.5425

Total time of 320 minutes for 37 jets, so

X = \frac{320}{37} = 8.65

This probability is the pvalue of Z when X = 8.65. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.65 - 8.3}{0.5425}

Z = 0.65

Z = 0.65 has a pvalue of 0.7422. This means that there is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

Total time of 275 minutes for 37 jets, so

X = \frac{275}{37} = 7.43

This probability is subtracted by the pvalue of Z when X = 7.43

Z = \frac{X - \mu}{\sigma}

Z = \frac{7.43 - 8.3}{0.5425}

Z = -1.60

Z = -1.60 has a pvalue of 0.0548.

There is a 1-0.0548 = 0.9452 = 94.52% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Total time of 320 minutes for 37 jets, so

X = \frac{320}{37} = 8.65

Total time of 275 minutes for 37 jets, so

X = \frac{275}{37} = 7.43

This probability is the pvalue of Z when X = 8.65 subtracted by the pvalue of Z when X = 7.43.

So:

From a), we have that for X = 8.65, we have Z = 0.65, that has a pvalue of 0.7422.

From b), we have that for X = 7.43, we have Z = -1.60, that has a pvalue of 0.0548.

So there is a 0.7422 - 0.0548 = 0.6874 = 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

7 0
3 years ago
I need help with this problem and show your work plz thanks
coldgirl [10]
Well is just their sum, thus

\bf \cfrac{3}{4}+\cfrac{2}{3}\impliedby \stackrel{LCD~is}{12}\implies \cfrac{(3)3+(4)2}{12}\implies \cfrac{9+8}{12}\implies \cfrac{17}{12}\implies 1\frac{5}{12}
5 0
3 years ago
Write a situation that could be represented by the algebraic expression 3a + 2.15.
nordsb [41]

Answer:

5.15

Step-by-step explanation:

5.15 = 3a + 2.15

5.15 - 2.15 = 3a

3.15 = 3a

a = 0.05

I hope this helps you :)

8 0
3 years ago
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