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blagie [28]
3 years ago
7

mark earned $1,650 per month period his new job pays 9.80 per hour what time and a half over 36 hours per week how many hours ov

ertime would he need to earn the same amount per week as his current job​
Mathematics
1 answer:
svet-max [94.6K]3 years ago
8 0

Answer:

Uhh

Step-by-step explanation:

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Draw a model <br> The sum of 3sixteen and 2 nines
borishaifa [10]
You would draw 48 counters and 18 counters which would be 66 counters in total. The picture is 1 of the sixteens and 1 of the nines. Sorry, if I misunderstood or got it wrong, I tried. If you don't understand something or I left out something, tell me in the comments.

7 0
4 years ago
a card is chosen at random from a deck of 52 cards. it is replaced and a second card is chosen. what is the probability of choos
serious [3.7K]
P(2 aces) = (1/13)^2 
P(2 kings) = (1/13)^2 

P(king and ace) = 8C2/52C2 - 2(1/13)^2 = 0.0152 
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4 years ago
Read 2 more answers
PLEASE HELP!!! <br> the last equation is “ 3/5x=12” answer that as well if you can
bazaltina [42]

Step-by-step explanation:

x= 20

3/5x= 12

3x= 12*5

x= 60/3= 20

Check

Putting x = 20 in 3/5x=12

LHS = 3/5*20

= 12

RHS = 12

LHS = RHS

7 0
4 years ago
a scientist makes sphere spherical magnets each wagon has a radius of 1.02 centimeters they are stored away in boxes of 250 calc
Triss [41]

Answer:

1,111 cm cubed

Hope it helps!

Step-by-step explanation:

1.02 (radius) cubed x 3.14 x 4/3     (sphere volume formula)

=4.44292416 cm cubed

4.44292416 x 250 (magnets amount) = 1,110.73104

1,110.73104 rounded to nearest whole cubic unit

1,111 cm cubed

3 0
4 years ago
Evidencia de aprendizaje Se desea obtener 80 kilogramos de café molido mezclando café arábico de S/18 el kilogramo y café torrad
SIZIF [17.4K]

Answer:

50kg de café torrado

30kg de café arábico

Step-by-step explanation:

Queremos obtener un total de 80kg de café molido.

Se utilizarán:

Café arábico, que cuesta $18 el kg

Café torrado, que cuesta $10 el kg

Queremos que el precio, por kilo, de la mezcla de 80kg sea $13.

Ok, primero debemos definir las variables:

Definamos:

x = cantidad de café arábico usado

y = cantidad de café torrado usado.

Entonces, como la mezcla deberá tener 80kg en total, tenemos:

x + y = 80kg

Y el costo total de esta mezcla será:

x*$18 + y*$10

Si lo dividimos por el peso total, tendremos el costo por kilo, que es:

(x*$18 + y*$10)/80kg

Y queremos que esto sea igual a $13, entonces tenemos la ecuación

(x*$18 + y*$10)/80kg = $13

Ok, ahora tenemos dos ecuaciones, es decir, tenemos un sistema de ecuaciones:

x + y = 80kg

(x*$18 + y*$10) = $13*80kg

(donde reescribimos levemente la segunda ecuación)

Ok, para resolver este sistema trataremos de reemplazar variables, para ello, el primer paso es aislar una de las variables en una de las ecuaciones.

Aislemos x en la primera:

x = 80kg - y

Ahora reemplazamos esto en la otra ecuación:

(x*$18 + y*$10) = $13*80kg

(( 80kg - y)*$18 + y*$10) = $13*80kg

Ahora podemos resolver esto para la variable y:

$18*80kg - $18*y + $10*y = $13*80kg

$18*80kg - $13*80kg = $18*y - $10*y

($18 - $13)*80kg = ($18 - $10)*y

$5*80kg = $8*y

($5*80kg)/$8 = y

50kg = y

Se usan 50kg de café torrado.

y como:

x + y = 80kg

x = 80kg - y

x = 80kg - 50kg = 30kg

Entonces los 30kg restantes serán de café arábico.

y la estrategia utilizada fue el remplazo de variables.

6 0
3 years ago
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