Answer:
Step-by-step explanation:
since the question does not have a given slope you can just put the point into the point slope formula y-y1 = m(x-x1)
y-5 = m(x-(-2))
y-5 = m(x+2)
since the slope is not given, leave it like that
The work done by the gas when the gas expands will be 567.65 ft-lb.
<h3>What is the work done for an isothermal process?</h3>
The Pressure is inversely proportional to the volume.
Let the initial pressure and initial volume be P₁ and V₁, and the final volume be V₂.
Then the work done by the gas will be
WD = P₁ V₁ ln (V₂ / V₁)
A quantity of the gas with an initial volume of 2 cubic feet and an initial pressure of 700 pounds per square foot.
The gas expands to a volume of 3 cubic feet.
Then the work done by the gas will be
WD = 700 x 2 x ln (3/2)
WD = 1400 x 0.405
WD = 567.65 ft-lb
The work done by the gas when the gas expands will be 567.65 ft-lb.
More about the work done for isothermal process link is given below.
brainly.com/question/4218306
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Angle 11 is 119
and select alternate interior angles theorem
Answer:
It will take at least 15 weeks
Step-by-step explanation:
12w+31 ≥ 205
Subtract 31 from each side
12w+31-31 ≥ 205-31
12w ≥ 174
Divide each side by 12
12w/12 ≥ 174/12
w ≥ 14.5
Rounding up to the nearest integer
w ≥ 15
It will take at least 15 weeks
13x - y = 3 .....(1)
x - 6y = -33 ......(2)
eqn (2) × 13
13x - 78y = -429 .....(3)
(3) - (1)
13x - 78y = -429
13x - y = 3
(-). (+). (-)
_________________
- 77y = 431
_________________
-77y = 431
y = 431 ÷ -77
y = -5.5
