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CaHeK987 [17]
3 years ago
7

You have 67.2 liters of oxygen at standard temperature and pressure. How many moles of oxygen molecules do you have? *

Chemistry
1 answer:
enot [183]3 years ago
3 0

Answer:

Number of moles is 3.0moles

Explanation:

Volume (v) = 67.2L

Pressure at STP = 1atm

Temperature at STP = 273.15K

R = 0.082J/mol.K

Number of moles (n) = ?

From ideal gas equation,

PV = nRT

P = pressure

V = volume of the gas

n = number of moles

R = ideal gas constant

T = temperature of the gas

PV = nRT

solving for n,

n = PV / RT

n = (1.0 * 67.2) / (0.082 * 273.15)

n = 67.2 / 22.398

n = 3.0 moles

The number of moles present is 3.0

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A particular reaction, A- products, has a rate that slows down as the reaction proceeds. The half-life of the reaction is found
Thepotemich [5.8K]

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a. As it is a second order reaction, therefore, doubling reactant concentration, will increase the rate of reaction 4 times. Therefore, the statement  a is wrong.

b. Expression for second order reaction is as follows:

\frac{1}{[A]} =\frac{1}{[A]_0} +kt

the above equation can be written in the form of Y = mx + C

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c.

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8 0
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What is the mole fraction of O2O2 in a mixture of 15.1 gg of O2O2, 8.19 gg of N2N2, and 2.46 gg of H2H2
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Answer:

Mole fraction O₂=  0.43

Explanation:

Mole fraction is the moles of gas/ total moles.

Let's determine the moles of each:

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Total moles = 2.183

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3 0
3 years ago
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