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NeTakaya
2 years ago
8

3. The opening that allows light to enter the eye is the

Chemistry
2 answers:
AlexFokin [52]2 years ago
5 0

Answer:

A. The opening that allows light to enter the eye is the iris.

Explanation:

xxMikexx [17]2 years ago
4 0

Answer:

A)  Iris

Explanation:

The Iris controls the diameter of the opening in your eye, thus also controlling the amount of light let inside. It's also reponsible for the colour of you eye.

You might be interested in
2HCl + CaCO3 → CaCl2 + H2O + CO2
zloy xaker [14]

Answer:

The amount of CaCl2 produced depends on the amount of HCl in the reaction.

Explanation:

The amount of HCl is used completelyin the reaction unlike CaCO3 which remains after reaction.

4 0
3 years ago
When copper is changed to copper(II) nitrate by the nitric acid, it is an example of a(n) ______-_______ reaction. (two words, i
Nataly_w [17]

Answer:

oxidation- reduction

Explanation:

where gaining electronic reduces one element and losing them oxidize the other nitric acid is not only strong it is also a oxidizing agent

<h2>Oxidize: copper = Cu+2</h2>
5 0
2 years ago
A 52.0 mL portion of a 1.20 M solution is diluted to a total volume of 278 mL. A 139 mL portion of that solution is diluted by a
RoseWind [281]

Answer:

C_3=0.125M

Explanation:

Hello!

In this case, we can divide the problem in two steps:

1. Dilution to 278 mL: here, the initial concentration and volume are 1.20 M and 52.0 mL respectively, and a final volume of 278 mL, it means that the moles remain the same so we can write:

V_1C_1=V_2C_2

So we solve for C2:

C_2=\frac{C_1V_1}{V_2}=\frac{52.0mL*1.20M}{278mL}\\\\C_2=0.224M

2. Now, since 111 mL of water is added, we compute the final volume, V3:

V_3=139+111=250mL

So, the final concentration of the 139 mL portion is:

C_3=\frac{139 mL*0.224M}{250mL}\\\\C_3=0.125M

Best regards!

8 0
3 years ago
What is the molarity of 50.84 g of Na2CO3 dissolved in 0.400 L solution?
borishaifa [10]

Answer:

1.20 M

Explanation:

Convert grams of Na₂CO₃ to moles.  (50.84 g)/(105.99 g/mol) = 0.4797 mol

Molarity is (moles of solute)/(liters of solvent) = (0.4797 mol)/(0.400 L) = 1.20 M

4 0
3 years ago
Butane, C4H10, reacts with oxygen, O2, to form water, H2O, and carbon dioxide, CO2, as shown in the following chemical equation:
Wittaler [7]
The balanced chemical reaction is:

<span>2C4H10(g)+13O2(g)->10H2O(g)+8CO2(g) 
</span>
<span>Calculate the mass of water produced when 1.77 grams of butane reacts with excessive oxygen?
</span>1.77 g C4H10 (1 mol C4H10/58.14 g C4H10) (10 mol H2O / 2 mol C4H10) ( 1.01 g H2O / 1 mol H2O ) = <span>0.15 g H2O

</span><span>Calculate the mass of butane needed to produce 71.6 of carbon dioxide.
</span>71.6 g CO2 (1 mol CO2/ 44.01 g CO2) ( 2 mol C4H10 / 8 mol CO2 ) (58.14 g C4H10 / 1 mol C4H10 ) = 23.65 g C4H10
4 0
3 years ago
Read 2 more answers
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