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3 years ago

7

A car is traveling at a speed of 60 kilometers per hour. what is the car's speed in miles per hour? how many miles will the car

travel in 3 hours?
(Assume that 1 mIle is 1.6 kilometers. Do not round your answers)

2 answers:

Ksju [112]3 years ago

7 0

Answer:

4.8

Step-by-step explanation

PilotLPTM [1.2K]3 years ago

5 0

60km/1.6 = 37.5mph

It will travel 3(37.5) = 112.5 miles.

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A rock is thrown up from the ground at a velocity of 84 feet per second. The formula h = -16t2 + 84t gives the rock's height in

kenny6666 [7]

Answer:

h = 110.24 m

Step-by-step explanation:

It is given that,

A rock is thrown up from the ground at a velocity of 84 feet per second. The formula $h = -16t^2 + 84t$ gives the rock's height in feet after t second.

We need to find the maximum height of the rock. For maximum height put $\dfrac{dh}{dt}=0$

So,

$\dfrac{d( -16t^2 + 84t)}{dt}=0\\\\-32t+84=0\\\\t=\dfrac{84}{32}\\\\t=2.62\ s$

Put t = 2.62 s in the equation of height. So,

$h = -16(2.62)^2 + 84(2.62)\\\\h=110.24\ m$

So, the maximum height of the rock is 110.24 m.

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3 years ago

Segment PE has endpoints P(-4,4) and E(0,-4). Find the coordinates of point Q such that PQ:QE is 1:3. Enter the coordinates belo

Natalka [10]

Answer:

(-3, 2)

Step-by-step explanation:

Given that point Q, partitions segment PE, such that PQ:QE is 1:3, coordinates of point Q is found using the formula below:

$x = \frac{mx_2 + nx_1}{m + n}$

$y = \frac{my_2 + ny_1}{m + n}$

Where,

$P(-4, 4) = (x_1, y_1)$

$E(0, -4) = (x_2, y_2)$

$m = 1, n = 3$

Plug in the necessary values to find x and y coordinates for point Q as follows:

$x = \frac{mx_2 + nx_1}{m + n}$

$x = \frac{1(0) + 3(-4)}{1 + 3}$

$x = \frac{0 - 12}{4}$

$x = \frac{-12}{4}$

$x = -3$

$y = \frac{my_2 + ny_1}{m + n}$

$y = \frac{1(-4) + 3(4)}{1 + 3}$

$y = \frac{-4 + 12}{4}$

$y = \frac{8}{4}$

$y = 2$

The coordinates of the point Q are (-3, 2))

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dangina [55]

Answer:

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Step-by-step explanation:

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Answer:

The solution is

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andrew11 [14]

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