All categories

2 years ago

If segment AB is 4 units, segment AD is 23 units, and segment CD is 12 units, what is the length of segment BC?

Mathematics

1 answer:

Thepotemich [5.8K]2 years ago

3 0

Answer:

<h2>C . 7 units</h2>

Step-by-step explanation:

The question is lacking appropriate diagram. Find the diagram to the question attached.

From the diagram, it can be seen that AD = AB+BC+CD

Given the following

AD = 23units

AB = 4units

CD = 12units

To get C=BC, we will substitute the given segments into the expression above as shown;

23 = 4+BC+12

23 = BC + 4 + 12

23 = BC+16

Subtract 16 from both sides

23-16 = BC+16-16

7 = BC

<em>Hence the length of segment BC is 7units.</em>

You might be interested in

Write the following as a ratio: $72 for 488 photos

weeeeeb [17]

Answer:

The required ratio is 9 : 61

Step-by-step explanation:

Given,

$72 for 488 photos,

That is, the price of 488 photos = 72 dollars,

So, the ratio of price of photos and number of photos = $\frac{72}{488}$

∵ HCF(72, 488) = 8,

Thus, the ratio of price of photos and number of photos = $\frac{72\div 8}{488\div 8}$

= $\frac{9}{61}$

3 0

3 years ago

Please help!!!!

vfiekz [6]

I solved this problem by setting 240/80 equal to x/100 . Once you set them equal to each other, multiply 240 and 100 and divide the product by 80 and you get 300.

3 0

2 years ago

The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s

Norma-Jean [14]

The positions when the particle reverses direction are:

$s(t_1)=55ft\\\\s(t_2)=28ft$

The acceleraton of the paticle when reverses direction is:

$a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}$

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

$s(t)=2t^{3}-21t^{2}+60t+3$