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Snezhnost [94]
3 years ago
9

If segment AB is 4 units, segment AD is 23 units, and segment CD is 12 units, what is the length of segment BC?

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
3 0

Answer:

<h2>C . 7 units</h2>

Step-by-step explanation:

The question is lacking appropriate diagram. Find the diagram to the question attached.

From the diagram, it can be seen that AD = AB+BC+CD

Given the following

AD = 23units

AB = 4units

CD = 12units

To get C=BC, we will substitute the given segments into the expression above as shown;

23 = 4+BC+12

23 = BC + 4 + 12

23 = BC+16

Subtract 16 from both sides

23-16 = BC+16-16

7 = BC

<em></em>

<em>Hence the length of segment BC is 7units.</em>

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Answer:

to be fair, i really dont know this

Step-by-step explanation:

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The sales tax on a $24 model rocket is $1.92 what is the percent of sales tax
AleksAgata [21]

Input data

Price model rocket = $24

Tax = $1.92

What is the percent of sales tax?

Procedure

r = percent of sales tax

r=\frac{1.92}{24}=0.08=8\text{ \%}

The answer would be 8%

8 0
1 year ago
What are the first five common multiples of 4 and 7
denis23 [38]
Easy, just write out the multiple of the numbers.

4: 4,8,12,16,20,24,28,32,36,40,44,48,52,56,60

7: 7,14,21,28,35,42,49,56,63,70 

Etc.

But a few common multiples:

28,56,84,112,140

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6 0
3 years ago
Help me and explain
yan [13]

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4 0
3 years ago
Suppose that profit for a particular product is calculated using the linear equation: Profit = 20S + 3D. Which of the following
uranmaximum [27]

Answer:

b. S = 405, D = 0

Step-by-step explanation:

We have been given that profit for a particular product is calculated using the linear equation: \text{Profit}=20S+3D. We are asked to choose the combinations of S and D that would yield a maximum profit.

To solve our given problem, we will substitute given values of S and D in the profit function one by one.

a. S = 0, D = 0

\text{Profit}=20S+3D

\text{Profit}=20(0)+3(0)

\text{Profit}=0

b. S = 405, D = 0

\text{Profit}=20S+3D

\text{Profit}=20(405)+3(0)

\text{Profit}=8100+0

\text{Profit}=8100

c. S = 0, D = 299

\text{Profit}=20S+3D

\text{Profit}=20(0)+3(299)

\text{Profit}=0+897

\text{Profit}=897

d. S = 182, D = 145

\text{Profit}=20S+3D

\text{Profit}=20(182)+3(145)

\text{Profit}=3640+435

\text{Profit}=4075

Since the combination S = 405, D = 0 gives the maximum profit ($8100), therefore, option 'b' is the correct choice.

7 0
3 years ago
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