IQR= Q3-Q1
Airport 1
Q3 is 8
Q1 is 2
8-2= 6
Airport 1 IQR is 6
Airport 2
Q3 is 8
Q1 is 3
8-3= 5
Airport 2 IQR Is 5
The expressions that are equivalent when m = 1 and m = 4 is;
Option B: 3m + 4 and m + 4 + 2m
We are given m = 1 and m =4;
A) 5m - 3 and 2m + 5 + m
B) 3m + 4 and m + 4 + 2m
C) 2m + 7 and 3m - 3 + m
D) 5m + 3 and 4m + 2 + 2m
For option B; 3m + 4 and m + 4 + 2m
Let's put m = 1
3(1) + 4 = 7
Also, 1 + 4 + 2(1) = 7
Similarly, let us put 4 for m to get;
3(4) + 4 = 16
Also, 4 + 4 + 2(4) = 16
In both cases, the expressions are equivalent and as such option B is the right one.
Read more about algebra simplifications at; brainly.com/question/4344214
total = 3000*(1-0.011)^10
1-0.011 = 0.989
total = 3000*(0.989)^10
0.989^10 = 0.895288314
3000* 0.895288314 = 2685.86
rounded to nearest whole number = 2686
there will be 2686 people
When simplified,letter A will be your answer.
4-7x=15
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
