Question

Write the net ionic equation (including phases) that corresponds to

Answer 1

                       Pb(NO₃)₂(aq) + K₂S(aq) → PbS(s) + 2KNO₃(aq)
Pb⁺(aq) + 2NO₃⁻(aq) + K₂⁺(aq) + S⁻(aq) → PbS(s) + K₂⁺(aq) + 2NO₃⁻(aq)
                                  Pb⁺(aq) + S⁻(aq) → PbS(s)

Answer 2

Answer: $Pb^{2+}(aq)+2S^{2-}(aq)\rightarrow PbS(s)$

Explanation:

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

$Pb(NO_3)_2(aq)+K_2S(aq)\rightarrow PbS(s)+2KNO_3(aq)$

$Pb^{2+}(aq)+2NO_3^-(aq)+2K^+(aq)+S^{2-}(aq)\rightarrow PbS(s)+2K^+(aq)+NO_3^-(aq)$

The ions which are present on both the sides of the equation are potassium and nitrate ions and hence are not involved in net ionic equation is:

Hence, the net ionic equation is $Pb^{2+}(aq)+2S^{2-}(aq)\rightarrow PbS(s)$